C++ Strings(字符串)

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 给出两个字符串,返回对应数字想乘后的字符串,由于这个字符串可能很大,所以不能采用一般的乘法,这里用的方法是模拟手工的乘法运算,算法 本身很简单,就是当时写的时候有些很小的细节搞错了,找了

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 这道题让我们求两个字符串数字的相乘,输入的两个数和返回的数都是以字符串格式储存的,这样做的原因可能是这样可以计算超大数相乘,可以不受int或long的数值范围的约束,那么我们该如何来计算

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 要求:字符串表示的数字可能无穷大,并且非负. class Solution { private: vector<string> tempStrs; public: string add

Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.

题意:定义a为一个字符串,a*a表示两个字符相连,即 an+1=a*an ,也就是出现循环了.给定一个字符串,若将其表示成an,问n最大为多少? 思路:如果完全不循环,顶多就是类似于abc1这样咯,即n=1.但是如果循环出现了,比如abab,那就可以表示成(ab)2.还有一点,就是要使得n尽量大,那么当出现abababab时,应该要这么表示(ab)4,而不是(abab)2. 此题用神奇的KMP解决,也就是主要利用next数组.举例说明. 一般出现循环的都会大概是这样的:abcabcabc.而这样

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. string multiply(string& num, char ch){ int n = ch - '0'; string s; int carry = 0; int x; for(

感觉题意不太好懂 = =# 给两个字符串 问是否等价等价的定义(满足其中一个条件):1.两个字符串相等 2.字符串均分成两个子串,子串分别等价 因为超时加了ok函数剪枝,93ms过的. #include <iostream> #include <cstring> #define clr(x,c) memset(x,c,sizeof(x)) using namespace std; const int N = 200005; char s[N], t[N]; int sc[30],

一.string (字符串) 1.set:设置键 $reids->set('mykey',111); 2.get:获取键 $redis->get('mykey'); 3.del:删除键 $redis->del('mykey'); 4.append:追加 $redis->append('mykey','222'); 5.exists:检查键是否存在 $reids->exists('mykey'); 6.incr/incrby,decr/decrby: 对键加减(键不存在默认为0

Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2. Note: The length of both num1 and num2 is < 110. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading z