【Leetcode 96】96. Unique Binary Search Trees

This is a BST(binary search tree) numbers counting problem but solved in dynamic programing.

https://discuss.leetcode.com/category/104/unique-binary-search-trees

This solution really gives me a shock. Before solving u need do some mathematical deduce in papers and get the dp function, which fantistically!

class Solution {
public:
    int numTrees(int n) {
        int G[100];
        for(int i = 0; i <= n; i ++)
            G[i] = 0;
        G[0] = G[1] = 1;
        for(int i = 2; i <= n; i ++){
            for(int j = 1; j <= i; j ++)
                G[i] += G[j - 1] * G[i - j];
        }
        return G[n];
    }
};
时间: 2024-12-17 11:51:24

【Leetcode 96】96. Unique Binary Search Trees的相关文章

LeetCode之“动态规划”:Unique Binary Search Trees &amp;&amp; Unique Binary Search Trees II

1. Unique Binary Search Trees 题目链接 题目要求: Given n, how many structurally unique BST's (binary search trees) that store values 1...n? For example, Given n = 3, there are a total of 5 unique BST's. 1 3 3 2 1 \ / / / \ 3 2 1 1 3 2 / / \ 2 1 2 3 题目分析参考自一博

【leetcode】23.Unique Binary Search Trees

以i为根节点时,其左子树构成为[0,...,i-1],其右子树构成为[i+1,...,n]构成.根结点确定时,左子树与右子树的结点个数都是确定的. 这样就可以把这个问题化成子问题.因此可以用动态规划解. Sigma(左边的子树可能状态 * 右边子树可能状态) = 当前个数的结点可能的状态数. ? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 public class Solution {     public int numTrees(int n

【一天一道LeetCode】#96. Unique Binary Search Trees

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given n, how many structurally unique BST's (binary search trees) that store values 1-n? For example, Given n = 3, there are a total of 5 unique BST's. (二)解题

【leetcode刷题笔记】Unique Binary Search Trees II

Given n, generate all structurally unique BST's (binary search trees) that store values 1...n. For example,Given n = 3, your program should return all 5 unique BST's shown below. 1 3 3 2 1 \ / / / \ 3 2 1 1 3 2 / / \ 2 1 2 3 题解:递归的枚举1~n的每个节点为根节点,然后递归

【LeetCode】Unique Binary Search Trees II 不同的二叉查找树II

今早起来做 LeetCode,结果被这道题卡了将近1个半小时,忍着没有去搜答案,最后还是被我想出来了,而且直接一次AC,哈哈!现在在这里记录一下解题思路. 原题: Given n, generate all structurally unique BST's (binary search trees) that store values 1...n. For example,Given n = 3, your program should return all 5 unique BST's sh

【LeetCode】Unique Binary Search Trees (2 solutions)

Unique Binary Search Trees Given n, how many structurally unique BST's (binary search trees) that store values 1...n? For example,Given n = 3, there are a total of 5 unique BST's. 1 3 3 2 1 \ / / / \ 3 2 1 1 3 2 / / \ 2 1 2 3 Base case: n==0, n==1时,f

96. Unique Binary Search Trees &amp;&amp; 95. Unique Binary Search Trees II &amp;&amp; 241. Different Ways to Add Parentheses

96. Unique Binary Search Trees Given n, how many structurally unique BST's (binary search trees) that store values 1...n? For example,Given n = 3, there are a total of 5 unique BST's. 1 3 3 2 1 \ / / / \ 3 2 1 1 3 2 / / \ 2 1 2 3 Tree Dynamic Program

LeetCode: Unique Binary Search Trees [095]

[题目] Given n, how many structurally unique BST's (binary search trees) that store values 1...n? For example, Given n = 3, there are a total of 5 unique BST's. 1 3 3 2 1 \ / / / \ 3 2 1 1 3 2 / / \ 2 1 2 3 [题意] 给定一个数字n, 问用1,2,3,4,5...n这n个值,能构造多少棵合法的二叉

LeetCode: Unique Binary Search Trees II [096]

[题目] Given n, generate all structurally unique BST's (binary search trees) that store values 1...n. For example, Given n = 3, your program should return all 5 unique BST's shown below. 1 3 3 2 1 \ / / / \ 3 2 1 1 3 2 / / \ 2 1 2 3 confused what "{1,#

[LeetCode][JavaScript]Unique Binary Search Trees II

Unique Binary Search Trees II Given n, generate all structurally unique BST's (binary search trees) that store values 1...n. For example,Given n = 3, your program should return all 5 unique BST's shown below. 1 3 3 2 1 \ / / / \ 3 2 1 1 3 2 / / \ 2 1