LeetCode OJ - Convert Sorted Array/List to Binary Search Tree

108. Convert Sorted Array to balanced Binary Search Tree The tricky part is the base case . Write induction part first and then test arrays of different size, 0, 1,2, 3 And finalize the base case /** * Definition for a binary tree node. * public clas

题目: Given an array where elements are sorted in ascending order, convert it to a height balanced BST 解答: 1 public class Solution { 2 3 public static void main(String[] args) { 4 int[] num = {1,2,3,4,5}; 5 6 TreeNode root = sortedArrayToBST(num); 7 8

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. class Solution { public: vector<int> Num; TreeNode *sortedArrayToBST(vector<int> &num) { if (num.size() == 0) return NULL; Num = num; return

题目:将非递减有序的链表转化为平衡二叉查找树! 参考的博客:http://blog.csdn.net/worldwindjp/article/details/39722643 利用递归思想:首先找到链表的中间节点,于是链表被分为了由该中间节点划分开来的两部分.递归地处理这两部分,最终便得到了平衡二叉查找树. 1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *n

(http://leetcode.com/2010/11/convert-sorted-list-to-balanced-binary.html) Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. Code: BinaryTree* sortedListToBST(ListNode *& list, int start, int

把一个排好序的vector转换为一颗二分查找树. 很简单的题目,递归即可,保证边界不要出错. 1 /** 2 * Definition for binary tree 3 * struct TreeNode { 4 * int val; 5 * TreeNode *left; 6 * TreeNode *right; 7 * TreeNode(int x) : val(x), left(NULL), right(NULL) {} 8 * }; 9 */ 10 class Solution { 1

原地归并. 下面是AC代码: 1 public void merge(int A[], int m, int B[], int n) { 2 3 int len = A.length; 4 //first copy m elements of A to the end of A 5 for(int i=m-1,j = len-1;i>=0;i--){ 6 A[j--] = A[i]; 7 } 8 //merge the A and B 9 int startA = len - m; 10 int

题目连接 https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ Convert Sorted Array to Binary Search Tree Description Given an array where elements are sorted in ascending order, convert it to a height balanced BST. /** * Definition f

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 题目标签:Tree 这道题目给了我们一个有序数组,从小到大.让我们把这个数组转化为height balanced BST. 首先来看一下什么是binary search tree: 每一个点的left < 节点 < right, 换一句话说,每一个点的值要大于左边的,小于右边的. 那么什么是heigh