快速幂模板

模板 快速幂模板 1 void solve(matrix t,long long o) 2 { 3 matrix e; 4 5 memset(e.a,0,sizeof(e.a)); 6 7 for (int i = 0;i < d;i++) 8 e.a[i][i] = 1; 9 10 while (o) 11 { 12 if (o & 1) 13 { 14 e = mul(e,t); 15 } 16 17 o >>= 1; 18 19 t = mul(t,t); 20 } 21

题目链接:http://www.51nod.com/onlineJudge/questionCode.html#!problemId=1113 题意:中文题诶- 思路:矩阵快速幂模板 代码: 1 #include <iostream> 2 #define ll long long 3 using namespace std; 4 5 const int mod = 1e9+7; 6 const int MAXN = 1e2+10; 7 int n, m; 8 9 typedef struct

转载请注明出处:http://blog.csdn.net/u012860063 或许你们看不太懂,纯属自用: 第一种: Description Let's define another number sequence, given by the following function: f(0) = a f(1) = b f(n) = f(n-1) + f(n-2), n > 1 When a = 0 and b = 1, this sequence gives the Fibonacci seq

矩阵快速幂模板 1 #include<stdio.h> 2 #include<math.h> 3 #include<set> 4 #include<string.h> 5 using namespace std; 6 int const mod=1e9+7; 7 struct matrix 8 { 9 long long m[3][3]; 10 matrix() 11 { 12 memset(m,0,sizeof(m)); 13 } 14 matrix op

Raising Modulo Numbers Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 4938   Accepted: 2864 Description People are different. Some secretly read magazines full of interesting girls' pictures, others create an A-bomb in their cellar, oth

快速幂模板: ll qmod(ll x,ll n,ll mod) { ll res=1; while(n){ if(n&1) res=(res*x)%mod; x=(x*x)%mod; n/=2; } return res; } 例题:hdu 1097 #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<cmath> usin

Tr A Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Description A为一个方阵,则Tr A表示A的迹(就是主对角线上各项的和),现要求Tr(A^k)%9973. Input 数据的第一行是一个T,表示有T组数据. 每组数据的第一行有n(2 <= n <= 10)和k(2 <= k < 10^9)两个数据.接下来有n行,每行有n

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1757 题目大意: 求递推式第k项模m If x < 10 f(x) = x.If x >= 10 f(x) = a0 * f(x-1) + a1 * f(x-2) + a2 * f(x-3) + -- + a9 * f(x-10);And ai(0<=i<=9) can only be 0 or 1 . 解题思路: 构建矩阵 直接用矩阵快速幂模板求解 注意,小于10的时候不能直接输出

Problem Description A为一个方阵,则Tr A表示A的迹(就是主对角线上各项的和),现要求Tr(A^k)%9973. Input 数据的第一行是一个T,表示有T组数据. 每组数据的第一行有n(2 <= n <= 10)和k(2 <= k < 10^9)两个数据.接下来有n行,每行有n个数据,每个数据的范围是[0,9],表示方阵A的内容. Output 对应每组数据,输出Tr(A^k)%9973. Sample Input 2 2 2 1 0 0 1 3 99999

原题 题目链接 题目分析 快速幂模板题,依题意套个求模快速幂,然后答案边加边模即可. 代码 1 #include <cstdio> 2 #include <cstdlib> 3 #include <iostream> 4 #include <algorithm> 5 #include <utility> 6 #include <ctime> 7 #include <cmath> 8 #include <cstring