PHP MYSQL 查询一段时间内的数据

查询半小时内数据的方法 1.select  * from 表名 where datediff(minute,createtime,getdate())<30 查询当天数据的方法 1.select  * from 表名 where datediff(day,createtime,getdate())=0 2.select  * from 表名 where convert(varchar(8),createtime,112)=convert(varchar(8),GETDATE(),112)   推

select * from zaiko where createtime between (now() - interval '3 Days') and now() ; select * from zaiko where createtime between (now() - interval '5 Mins') and now() ps经过实际核实,这方法有毛病,刚入的数据,几十秒之后才能刷的出来 原文地址:https://www.cnblogs.com/xiaoliu66007/p/1134

如我要取8月1号到8月30号之间的早上7点半到晚上八点半这段时间内的数据. SELECT * FROM tableName AS tWHERE t.create_date BETWEEN '2017-08-01 07:30' AND '2017-08-30 20:30' AND CONVERT(CHAR(5), t.create_date, 14) BETWEEN '07:30' AND '20:30'————————————————版权声明:本文为CSDN博主「life_is_crazy」的原

在mysql中查询不区分大小写重复的数据,往往会用到子查询,并在子查询中使用upper函数来将条件转化为大写.如: select * from staticcatalogue WHERE UPPER(Source) IN (SELECT UPPER(Source) FROM staticcatalogue GROUP BY UPPER(Source) having count(UPPER(Source))>1) ORDER BY upper(Source) DESC; 这条语句的执行效率是非常低

SET FOREIGN_KEY_CHECKS=0; -- Table structure for t_user -- ---------------------------- DROP TABLE IF EXISTS t_user; CREATE TABLE t_user ( userId bigint(20) NOT NULL, fullName varchar(64) NOT NULL, userType varchar(16) NOT NULL, addedTime datetime NO

SELECT  CONVERT(VARCHAR(10), dtCreateTime, 120) AS dtStatisticsCreateDate, COUNT(1) AS nStatisticsCount                    FROM    Web_Statistics                    WHERE datepart(hh,dtCreateTime)>=10 AND datepart(hh,dtCreateTime)<11

24小时内记录(即86400秒) $sql="SELECT video_id,count(id)as n FROM `rec_down` WHERE UNIX_TIMESTAMP(NOW())-UNIX_TIMESTAMP(add_time)<=86400 group by video_id order by n desc ";$sql="select a.id,a.title,b.n from video_info a,(".$sql.")b wh

things相当于一个已经创建好的表 命令: db.things.find({"createTime":{"$gt":"2015-5-21 0:0:0"}}) // 大于某个时间db.things.find({"createTime":{"$lt":"2014-5-21 0:0:0"}}) // 小于某个时间db.things.find({"$and":[{"

今天的数据 SELECT * FROM `statements` WHERE DATE_FORMAT( FROM_UNIXTIME( `happen_time` ) , '%Y-%m-%d' ) = DATE_FORMAT( NOW( ) , '%Y-%m-%d' ) 昨天的数据 SELECT * FROM statements where `happen_time`>UNIX_TIMESTAMP(DATE_SUB(CURDATE(), INTERVAL 1 DAY))