同样的代码在java和c++中结果不同

 1 #include <iostream>
 2 using namespace std;
 3 /* run this program using the console pauser or add your own getch, system("pause") or input loop */
 4 class A {
 5     public:
 6         void m() {
 7             n();
 8         }
 9
10     public:
11         virtual void n() {
12             cout<<"调用了父类的n函数";
13         }
14
15 };
16
17 class B:public A {
18
19     public:
20         void m() {
21             A::m();
22         }
23
24     public:
25         void n() {
26             cout<<"调用了子类的n函数";
27         }
28
29 };
30 int main(int argc, char** argv) {
31     B b;
32     b.m();
33     return 0;
34 }

class A
{
public void m()
{
	n();
}
public void n()
{
System.out.println("调用了父类的n函数");
}
}

class B extends A
{

public void m()
{
	super.m();
}

public void n()
{
System.out.println("调用了子类的n函数");
}
}

public class main {
	public static void main(String[] args) {
		// TODO Auto-generated method stub
    B b=new B();
    b.m();
	}
}

c++输出父类，java输出子类。　　

原因java默认多态，动态绑定。c++需要加virtual,加上后均为子类