1. 题目
Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World"
,
return 5
.
2.解决方式
class Solution { public: int lengthOfLastWord(const char *s) { int len = strlen(s); int result = 0; while(s[len-1]==‘ ‘) len--; for(int i = len - 1; i >= 0; --i){ if(s[i] != ‘ ‘){ ++result; }else{ break; } } return result; } };
思路:还是比較easy的,就是要先把后面的‘ ’都先干掉。
http://www.waitingfy.com/archives/1645
时间: 2024-09-29 13:19:02