LeetCode 380. Insert Delete GetRandom O(1)

380. Insert Delete GetRandom O(1)

Add to List

Description Submission Solutions

• Total Accepted: 21771
• Total Submissions: 56175
• Difficulty: Medium
• Contributors: Admin

Design a data structure that supports all following operations in average O(1) time.

1. insert(val): Inserts an item val to the set if not already present.
2. remove(val): Removes an item val from the set if present.
3. getRandom: Returns a random element from current set of elements. Each element must have the same probability of being returned.

Example:

// Init an empty set.
RandomizedSet randomSet = new RandomizedSet();

// Inserts 1 to the set. Returns true as 1 was inserted successfully.
randomSet.insert(1);

// Returns false as 2 does not exist in the set.
randomSet.remove(2);

// Inserts 2 to the set, returns true. Set now contains [1,2].
randomSet.insert(2);

// getRandom should return either 1 or 2 randomly.
randomSet.getRandom();

// Removes 1 from the set, returns true. Set now contains [2].
randomSet.remove(1);

// 2 was already in the set, so return false.
randomSet.insert(2);

// Since 2 is the only number in the set, getRandom always return 2.
randomSet.getRandom();

Subscribe to see which companies asked this question.

【题目分析】

设计一种数据结构，使得插入，删除和随机获取一个值的时间复杂度为O(1).

【思路】

1. 随机读取一个数的话，使用数组的时间复杂度是最小的，因为通过下标可以直接定位。考虑到元素会不断插入，我们可以选择ArrayList来存储我们的元素。

2. 要删除一个元素，在数组中需要遍历才能找到这个元素。而在HashMap中，可以快速定位一个元素。因此我们可以用HashMap来存储元素和它在ArrayList中对应的下标。

通过以上的分析，我们知道了数据结构该如何设计。

【java代码】

 1 public class RandomizedSet {
 2     Map<Integer, Integer> map;
 3     List<Integer> list;
 4     Random random;
 5
 6     /** Initialize your data structure here. */
 7     public RandomizedSet() {
 8         map = new HashMap<>();
 9         list = new ArrayList<>();
10         random = new Random();
11     }
12
13     /** Inserts a value to the set. Returns true if the set did not already contain the specified element. */
14     public boolean insert(int val) {
15         if(map.containsKey(val)) return false;
16         map.put(val, list.size());
17         list.add(val);
18         return true;
19     }
20
21     /** Removes a value from the set. Returns true if the set contained the specified element. */
22     public boolean remove(int val) {
23         if(!map.containsKey(val)) return false;
24         int loc = map.get(val);
25         if(loc < list.size()-1) {
26             int last = list.get(list.size()-1);
27             list.set(loc, last);
28             map.put(last, loc);
29         }
30         map.remove(val);
31         list.remove(list.size()-1);
32         return true;
33     }
34
35     /** Get a random element from the set. */
36     public int getRandom() {
37         return list.get(random.nextInt(list.size()));
38     }
39 }
40
41 /**
42  * Your RandomizedSet object will be instantiated and called as such:
43  * RandomizedSet obj = new RandomizedSet();
44  * boolean param_1 = obj.insert(val);
45  * boolean param_2 = obj.remove(val);
46  * int param_3 = obj.getRandom();
47  */