[LeetCode] Construct Binary Tree from Inorder and Postorder Traversal

Given inorder and postorder traversal of a tree, construct the binary tree.

Note: You may assume that duplicates do not exist in the tree.

class Solution {
public:
    TreeNode *buildTree(vector<int> &inorder, vector<int> &postorder) {
        int len = inorder.size();
        return build(inorder,0,len-1,postorder,0,len-1);
    }
private:
    TreeNode * build(vector<int> &inorder,int begInorder,int endInorder, vector<int> &postorder,int begpostorder,int endpostorder){

        if(begInorder>endInorder || begpostorder>endpostorder)
            return NULL;

        int val = postorder[endpostorder];
        TreeNode *root = new TreeNode(val);
        if(endInorder==begInorder)
            return root;
        int i,j=0;
        for(i=begInorder;i<=endInorder;i++,j++){
           if(inorder[i]==val)
               break;
        }

        root->left = build(inorder,begInorder,i-1,postorder,begpostorder,begpostorder+j-1);
        root->right = build(inorder,i+1,endInorder,postorder,begpostorder+j,endpostorder-1);
        return root;

    }
};

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