将Excel导入DataGridView 中的"select * from [Sheet1$]"中[ ]里面表单名的动态获取

Sheet1$是Excel默认的第一个表名，如果改动：select * from
[Sheet1$]"将查询失败，因此应根据选择自动获取excel表名：

 1 OpenFileDialog ofd = new OpenFileDialog();  //选择文件路径

 2     ofd.Title = "Excel文件";

 3     ofd.FileName = "";

 4     ofd.Filter = "Excel文件(*.xls)| *.xls";

 5 string Path = ofd.FileName;

 6 string tableName = "";

 7

 8 string strConn = "Provider=Microsoft.Jet.OLEDB.4.0;" + "Data Source=" + Path + ";" + "Extended Properties=Excel 8.0;";

 9 OleDbConnection conn = new OleDbConnection(strConn);

10 conn.Open();

11 System.Data.DataTable sTable = conn.GetOleDbSchemaTable(System.Data.OleDb.OleDbSchemaGuid.Tables, null);

12 tableName = sTable.Rows[0][2].ToString().Trim();

13

14 for (int i = 0; i < sTable.Rows.Count; i++)

15 {

16     schemaTable.Rows[i][2].ToString().TrimStart(‘\‘‘).Trim(‘\‘‘, ‘$‘);

17 }

18

19 string strExcel = "select * from [" + tableName + "]";

20 OleDbDataAdapter myCommand = new OleDbDataAdapter(strExcel, strConn);

21 DataSet ds = new DataSet();

22 DataTable table1 = new DataTable();

23 myCommand.Fill(table1);

24 //==========最后绑定

25 dataGridView1.DataSource = table1;

将Excel导入DataGridView 中的"select * from [Sheet1$]"中[
]里面表单名的动态获取,布布扣,bubuko.com

将Excel导入DataGridView 中的"select * from [Sheet1$]"中[
]里面表单名的动态获取