Guess the number
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 3035 Accepted Submission(s): 2281
Problem Description
Happy new year to everybody!
Now, I want you to guess a minimum number x betwwn 1000 and 9999 to let
(1) x % a = 0;
(2) (x+1) % b = 0;
(3) (x+2) % c = 0;
and a, b, c are integers between 1 and 100.
Given a,b,c, tell me what is the number of x ?
Input
The number of test cases c is in the first line of input, then c test cases followed.every test contains three integers a, b, c.
Output
For each test case your program should output one line with the minimal number x, you should remember that x is between 1000 and 9999. If there is no answer for x, output "Impossible".
Sample Input
2 44 38 49 25 56 3
Sample Output
Impossible 2575
Author
8600
Source
做这题目简直浪费时间
#include<iostream>
using namespace std;
int main()
{
int n,a,b,c,i;
cin>>n;
while(n--)
{
cin>>a>>b>>c;
for(i=1000;i<=9999;i++)
if((i%a==0)&&((i+1)%b==0)&&((i+2)%c==0))
{
cout<<i<<endl;;
break;
}
if(i>9999)
cout<<"Impossible"<<endl;
}
return 0;
}