Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution.
Example:
Given nums = [2, 7, 11, 15], target = 9, Because nums[0] + nums[1] = 2 + 7 = 9, return [0, 1]. 代码如下:
1 class Solution { 2 public: 3 vector<int> twoSum(vector<int>& nums, int target) 4 { 5 unordered_map<int, int> hashmap; 6 vector<int> result; 7 8 for (int i = 0; i < nums.size(); ++i) 9 { 10 if (hashmap.find(target - nums[i]) != hashmap.end()) 11 { 12 result.push_back(hashmap[target - nums[i]]); 13 result.push_back(i); 14 return result; 15 } 16 else 17 { 18 hashmap[nums[i]] = i; 19 } 20 } 21 return result; 22 } 23 };
时间: 2024-10-24 11:33:50