BEGIN
declare p_id INT;
declare p_Code INT default 0;
declare p_Logo
INT default 0;
declare p_Name varchar(255) default ‘‘;
declare p_Address
varchar(755) default ‘‘;
declare p_Phone varchar(755) default ‘‘;
declare
p_Logo2 varchar(755) default ‘‘;
declare p_Logo3 varchar(755) default
‘‘;
declare p_Paid varchar(755) default ‘‘;
declare p_IsDelete
varchar(755) default ‘‘;
declare done INT DEFAULT 0;
declare cur CURSOR
FOR SELECT ID, Code,Logo,Name,Address,Phone,Logo2,Logo3,Paid,IsDelete FROM
hospital_copy;
declare CONTINUE HANDLER FOR NOT FOUND SET done=1;
OPEN
cur;
REPEAT
FETCH cur INTO p_id,
p_Code,p_Logo,p_Name,p_Address,p_Phone,p_Logo2,p_Logo3,p_Paid,p_IsDelete;
IF done=0 THEN
INSERT INTO
`hospital` (
`ID` ,
`Code` ,
`Name` ,
`Country_Code` ,
`Phone`
,
`Address1` ,
`Address2`
,
`Address3` ,
`County`
,
`Country` ,
`Postcode`
,
`Logo`
,
`Logo2` ,
`Logo3`
,
`Paid`
,
`IsDeleted`,
`Add_time`,
`Delete_time`,
`timeInterval`
)
VALUES (
p_id,
p_Code,p_Name,‘0001‘,‘13971056776‘,p_Address,p_Address, p_Address, p_Address,
p_Address, ‘442200‘,
p_Logo,p_Logo2,p_Logo3,p_Paid,p_IsDelete,‘2011-1-1‘,‘‘,‘30‘);
END IF;
UNTIL
done=1
END REPEAT;
CLOSE
cur;
END
加深红色部分解决方法,最后的重复的原因是FETCH cur INTO
……;的时候,当第一次到达最后一条记录时,取出记录,把值给变量,这时一切正常,没有错误。然后UNTIL UNTIL done=1
循环到REPEAT重新开始,再FETCH一条时,已经没有记录,done会被 SET
done=1;,但此刻没有进行任何判断,程序会继续执行INSERT INTO
……语句,而由于FETCH没有取到记录,则没有对变量进行赋值,所以变量仍是原值。当到UNTIL done 时程序退出REPEAT,从而最后的记录会被重复。