1083 List Grades (25 分)
Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.
Input Specification:
Each input file contains one test case. Each case is given in the following format:
N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2
where name[i]
and ID[i]
are strings of no more than 10 characters with no space, grade[i]
is an integer in [0, 100], grade1
and grade2
are the boundaries of the grade‘s interval. It is guaranteed that all the grades are distinct.
Output Specification:
For each test case you should output the student records of which the grades are in the given interval [grade1
, grade2
] and are in non-increasing order. Each student record occupies a line with the student‘s name and ID, separated by one space. If there is no student‘s grade in that interval, output NONE
instead.
Sample Input 1:
4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100
Sample Output 1:
Mike CS991301
Mary EE990830
Joe Math990112
Sample Input 2:
2
Jean AA980920 60
Ann CS01 80
90 95
Sample Output 2:
NONE
思路: 排序包括区间端点
#include<iostream> #include<vector> #include<algorithm> #include<queue> #include<string> #include<map> #include<set> using namespace std; struct Node { string name; string id; int grade; }; bool cmp(Node&A,Node&B) { return A.grade>B.grade; } int main() { int n; cin>>n; Node node[n]; for(int i=0;i<n;i++) cin>>node[i].name>>node[i].id>>node[i].grade; int grade1,grade2; cin>>grade1>>grade2; sort(node,node+n,cmp); bool flag=false; for(int i=0;i<n;i++) { if(node[i].grade>=grade1&&node[i].grade<=grade2) { cout<<node[i].name<<" "<<node[i].id<<endl; flag=true; } } if(flag) cout<<"NONE"; return 0; }
原文地址:https://www.cnblogs.com/zhanghaijie/p/10308233.html