题目描述:
The gray code is a binary numeral system where two successive values differ
in only one bit.
Given a non-negative integer n representing the total
number of bits in the code, print the sequence of gray code. A gray code
sequence must begin with 0.
For example, given n = 2,
return [0,1,3,2]
. Its gray code sequence is:
00 - 0
01 - 1
11 - 3
10 - 2
Note:
For a given n, a gray code sequence
is not uniquely defined.
For example, [0,2,3,1]
is also a valid gray code
sequence according to the above definition.
For now, the judge is able to judge based on one instance of gray code
sequence. Sorry about that.
考察位操作:
从题目中例子可以发现这么一个规律:
假设结果数组为B,原始数组为A,则有:B[i] = A[i] ^ (A[i]>>1).
例如 : A[3] =3
B[3] = 3^(3>>1)
= 011^001
= 010 = 2
解法如下:
1 class Solution {
2 public:
3 vector<int> grayCode(int n) {
4 int len = pow(2.0,n),i,a;
5 vector<int> vi;
6 for(i=0;i<len;i++)
7 {
8 a= i^(i>>1);
9 vi.push_back(a);
10 }
11 return vi;
12 }
13 };
时间: 2024-10-24 09:20:52