C++异常捕获与解决函数多参数返回

捕获异常

double divideNumber(double num1,double num2){

	if (num2==0) {
		throw exception();
	}
	return num1/num2;
}

	try{
		cout << divideNumber(1,3) << endl;
		cout << divideNumber(1,0) << endl;
	}catch(const exception& exp) {
		cout << "An exception was caught !" << endl;
	}

函数多参数返回（不通过返回参数）

void addNum(int& a)
{
	a++;
}