The kth great number

Problem Description

Xiao Ming and Xiao Bao are playing a simple Numbers game. In a round Xiao Ming can choose to write down a number, or ask Xiao Bao what the kth great number is. Because the number written by Xiao Ming is too much, Xiao Bao is feeling giddy. Now, try to help
Xiao Bao.

Input

There are several test cases. For each test case, the first line of input contains two positive integer n, k. Then n lines follow. If Xiao Ming choose to write down a number, there will be an " I" followed by a number that Xiao Ming will write down. If Xiao
Ming choose to ask Xiao Bao, there will be a "Q", then you need to output the kth great number.

Output

The output consists of one integer representing the largest number of islands that all lie on one line.

Sample Input

8 3
I 1
I 2
I 3
Q
I 5
Q
I 4
Q

Sample Output

1
2
3

Hint

Xiao  Ming  won‘t  ask  Xiao  Bao  the  kth  great  number  when  the  number  of  the  written number is smaller than k. (1=<k<=n<=1000000).

Source

The 36th ACM/ICPC
Asia Regional Dalian Site —— Online Contest

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题目大意：

有m组操作，求第K大数。I为insert操作，即插入1个数，Q为询问，输出此时的第K大数。

解题思路：

一道水题让我智商捉鸡了，居然笨到想去用线段树去做。后来发现1个set搞定，就存K个大数，超过的把小的踢掉，输出第一个即可。

解题代码：

#include <iostream>
#include <cstdio>
#include <set>
#include <algorithm>
using namespace std;

int n,k;
multiset <long long> mys;

void solve(){
    mys.clear();
    char ch;
    int x;
    for(int i=0;i<n;i++){
        scanf("\n");
        scanf("%c",&ch);
        if(ch=='I'){
            scanf("%lld",&x);
            mys.insert(x);
            if(mys.size()>k) mys.erase(mys.begin());
        }else{
            cout<<*mys.begin()<<endl;
        }
    }
}

int main(){
    while(scanf("%d%d",&n,&k)!=EOF){
        solve();
    }
    return 0;
}

HDU 4006 The kth great number （基本算法-水题）,布布扣,bubuko.com