[LeetCode] Implement Rand10() Using Rand7()

题目描述

Given a function rand7 which generates a uniform random integer in the range 1 to 7, write a function rand10 which generates a uniform random integer in the range 1 to 10.

Do NOT use system’s Math.random().

Example 1:

Input: 1
Output: [7]

Example 2:

Input: 2
Output: [8,4]

Example 3:

Input: 3
Output: [8,1,10]

Note:

rand7 is predefined.
Each testcase has one argument: n, the number of times that rand10 is called.

rand7 返回均匀分布的1到7，要求根据rand7 实现一个rand10, 要求返回均匀分布的1到10。
解决思路是先构建一个randN, N 要求是 10 的整数倍。由randN % 10 可以得到rand10。
由rand7 可以得到 rand49 , rand49 通过过滤掉大于等于40 的可以得到 rand40, 进而可以得到rand10。综上，解决思路如下：

rand7 -> rand49 -> rand40 -> rand10

此解决方案可以推广到所有randN 生成randM (N < M) 的场景。

C++ 实现

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// int rand7();// @return a random integer in the range 1 to 7

class  {public:    int rand10() {        const int num = rand40();        return num % 10 + 1;    }private:    // return 0 ~ 48 randomly    int rand49()    {        return 7 * (rand7() - 1) + rand7() - 1;    }    // return 0 ~ 39 randomly    int rand40()    {        int num = rand49();        while(num >= 40)        {            num = rand49();        }        return num;    }};

原文地址：https://www.cnblogs.com/liuzhongrong/p/11874866.html