第一步引入jquery.js
html代码如下
<form name="post" id="post" method="post" action="/Login"> <input type="text" name="username" value="" /> <input type="password" name="password" value="@Model.linkorig" /> <input type="button" value="提交" onclick="Submit()"> </form>
js如下
function Submit() { var username = $("#username").val(); $.get("/Ajax/CheckName", { name: username }, function (data) { if (!data.Success) { alert(data.Msg); return; } else { document.post.submit(); } } , "json"); }
后台如下
public JsonResult CheckName(string name)
{
JsonData _jsondata = new JsonData();
JsonResult jsn = new JsonResult();
jsn.JsonRequestBehavior = JsonRequestBehavior.AllowGet;
//检查用户名是否存在代码---省略
//返回json
_jsondata.Success = false;
_jsondata.Msg = "用户名不存在!";
jsn.Data = _jsondata;
return jsn;
}
时间: 2024-08-24 15:58:02