Fractal
Time Limit: 1000MS | Memory Limit: 30000K | |
Total Submissions: 8341 | Accepted: 3965 |
Description
A fractal is an object or quantity that displays self-similarity, in a somewhat technical sense, on all scales. The object need not exhibit exactly the same structure at all scales, but the same "type" of structures must appear on all scales.
A box fractal is defined as below :
- A box fractal of degree 1 is simply
X - A box fractal of degree 2 is
X X
X
X X - If using B(n - 1) to represent the box fractal of degree n - 1, then a box fractal of degree n is defined recursively as following
B(n - 1) B(n - 1) B(n - 1) B(n - 1) B(n - 1)
Your task is to draw a box fractal of degree n.
Input
The input consists of several test cases. Each line of the input contains a positive integer n which is no greater than 7. The last line of input is a negative integer −1 indicating the end of input.
Output
For each test case, output the box fractal using the ‘X‘ notation. Please notice that ‘X‘ is an uppercase letter. Print a line with only a single dash after each test case.
Sample Input
1 2 3 4 -1
Sample OutputX
- X X X X X - X X X X X X X X X X X X X X X X X X X X X X X X X - X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X -递归:思路很巧妙,把每个左上角的点作为起点;开始递归;代码:
#include<iostream> #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include<queue> using namespace std; const int INF=0x3f3f3f3f; #define mem(x,y) memset(x,y,sizeof(x)) #define SI(x) scanf("%d",&x); char a[2500][2500]; void dfs(int x,int y,int cur){ if(cur==1){ a[x][y]=‘X‘; return; } int n,m; dfs(x,y,cur-1); //左上 m=x;n=y+pow(3,cur-2)*2; dfs(m,n,cur-1); //右上 m=x+pow(3,cur-2)*2;n=y; dfs(m,n,cur-1); //左下 m=x+pow(3,cur-2)*2;n=y+pow(3,cur-2)*2; dfs(m,n,cur-1); //右下 m=x+pow(3,cur-2);n=y+pow(3,cur-2); dfs(m,n,cur-1); //中 } int main(){ int N; while(scanf("%d",&N),N!=-1){ int len=pow(3,N-1); for(int i=0;i<len;i++){ for(int j=0;j<len;j++) a[i][j]=‘ ‘; a[i][len]=‘\0‘; } dfs(0,0,N); for(int i=0;i<len;i++){ printf("%s\n",a[i]); } puts("-"); } return 0; }