[LeetCode] 405. Convert a Number to Hexadecimal_Easy tag: Bit Manipulation

Given an integer, write an algorithm to convert it to hexadecimal. For negative integer, two’s complement method is used.

Note:

1. All letters in hexadecimal (a-f) must be in lowercase.
2. The hexadecimal string must not contain extra leading 0s. If the number is zero, it is represented by a single zero character ‘0‘; otherwise, the first character in the hexadecimal string will not be the zero character.
3. The given number is guaranteed to fit within the range of a 32-bit signed integer.
4. You must not use any method provided by the library which converts/formats the number to hex directly.

Example 1:

Input:
26

Output:
"1a"

Example 2:

Input:
-1

Output:
"ffffffff"

Code    T: O(1)

class Solution:
    def toHex(self, num):
        ans, d = "", {10:‘a‘, 11:‘b‘, 12:‘c‘, 13:‘d‘, 14:‘e‘, 15:‘f‘}
        if num == 0:
            return "0"
        if num < 0:
            num = 2**32 + num
        while num > 0:
            tem, rem = divmod(num, 16)
            if rem > 9:
                ans += d[rem]
            else:
                ans += str(rem)
            num = tem
        return ans[::-1]

原文地址：https://www.cnblogs.com/Johnsonxiong/p/9545947.html