今天用python完成的是带进度条的圆周率计算

代码如下：

import math
import time
scale=14
s,m,=1,2
print("执行开始".center(scale//2, "-"))
start = time.perf_counter()
for i in range(scale+1):
    s=math.sqrt((1-math.sqrt(1-pow(s,2)))/2)
    m=m*2
    a = ‘*‘ * i
    b = ‘.‘ * (scale - i)
    c = (i/scale)*100
    dur = time.perf_counter() - start
    print("\r{:^3.0f}%[{}->{}]{:.2f}s".format(c,a,b,dur))
time.sleep(0.1)
Pi=s*m
print("Pi值是{}".format(Pi))
print("\n"+"执行结束".center(scale//2,‘-‘))

代码运行结果：

原文地址：https://www.cnblogs.com/1234ai/p/10549763.html