The Problem

Median plays an important role in the world of statistics. By definition, it is a value which divides an array into two equal parts. In this problem you are to determine the current median of some long integers.

Suppose, we have five numbers {1,3,6,2,7}. In this case, 3 is the median as it has exactly two numbers on its each side. {1,2} and {6,7}.

If there are even number of values like {1,3,6,2,7,8}, only one value cannot split this array into equal two parts, so we consider the average of the middle values {3,6}. Thus, the median will be (3+6)/2 = 4.5.
In this problem, you have to print only the integer part, not the fractional. As a result, according to this problem, the median will be 4!

Input

The input file consists of series of integers X ( 0 <= X < 2^31 ) and total number of integers N is less than 10000. The numbers may have leading or trailing spaces.

Output

For each input print the
current value of the median.

Sample Input

1
3
4
60
70
50
2

Sample Output

1
2
3
3
4
27
4

2001-04-01

题意有些难读懂。

#include <cstdio>
#include <algorithm>
using std:: sort;
int arr[10002], id;

int main()
{
	int n;
	while(scanf("%d", &n) != EOF){
		arr[id++] = n;
		sort(arr, arr + id);

		if(id & 1) printf("%d\n", arr[id / 2]);
		else printf("%d\n", (arr[id / 2] + arr[id / 2 - 1]) / 2);
	}
	return 0;
}

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