Least Common Multiple

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 30285    Accepted Submission(s): 11455

Problem Description

The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.

Input

Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.

Output

For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.

Sample Input

2

3

5 7 15

6

4 10296 936 1287 792 1

Sample Output

105

10296

Source

East Central North America 2003, Practice

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 1 #include<cstdio>
 2 #include<cstring>
 3 #include<stdlib.h>
 4 #include<algorithm>
 5 using namespace std;
 6 int gcd(int a,int b)
 7 {
 8     return b?gcd(b,a%b):a;
 9 }
10 int lcm(int a,int b)
11 {
12     return a/gcd(a,b)*b;
13 }
14 int main()
15 {
16     //freopen("in.txt","r",stdin);
17     int kase,m;
18     scanf("%d",&kase);
19     while(kase--)
20     {
21         int ans,num;
22         scanf("%d",&m);
23         for(int i=0;i<m;i++)
24         {
25             int A;
26             scanf("%d",&A);
27             if(i==0){ans=A;continue;}
28             num=A;
29             ans=lcm(ans,num);
30         }
31         printf("%d\n",ans);
32     }
33     return 0;
34 }

HDU 1019 Least Common Multiple (最小公倍数),布布扣,bubuko.com