instance与type区别

class Foo(object):
pass

class Bar(Foo):
pass

obj = Bar()

# isinstance用于判断,对象是否是指定类的实例 (错误的)
# isinstance用于判断,对象是否是指定类或其派生类的实例
print(isinstance(obj,Foo)) #True
print(isinstance(obj,Bar))#True
#精确的
print(type(obj) == Bar) #True
print(type(obj) == Foo) #False

  

时间: 2024-08-06 05:38:42

instance与type区别的相关文章

No enclosing instance of type Hello is accessible

1.static 关键字 修饰的成员被所有对象共享(包括成员变量和方法). 修饰的成员优先于对象存在. 存储于方法区(共享数据区)的静态区中. 静态方法只能访问静态成员. 静态方法中不可以使用this或super关键字. 主函数是static,只能调用static方法. 静态代码块随着类的加载而运行(只执行一次).用于给类进行初始化. Q: I have the following code: 1: class Hello { 2: class Thing { 3: public int siz

Java 出现 No enclosing instance of type Test1 is accessible.(转,自己也遇到了!)

最近在看Java,在编译写书上一个例子时,由于书上的代码只有一部分,于是就自己补了一个内部类.结果编译时出现:No enclosing instance of type E is accessible. Must qualify the allocation with an enclosing instance of type E(e.g.  x.new A() where x is an instance of E). E指代我写的那个内部类. 根据提示,没有可访问的内部类E的实例,必须分配一

linux中查找命令find、locate、whereis、which、type区别

linux中查找命令find.locate.whereis.which.type区别 1. find Java代码 find是最常见和最强大的查找命令,你可以用它找到任何你想找的文件.与查询数据库(/var/lib/locatedb)文件不同,find查找磁盘空间 find的使用格式如下: $ find <指定目录> <指定条件> <指定动作> - <指定目录>: 所要搜索的目录及其所有子目录.默认为当前目录. - <指定条件>: 所要搜索的文件

android No enclosing instance of type BasicActivity is accessible. Must qualify the allocation with

No enclosing instance of type BasicActivity is accessible. Must qualify the allocation with an enclosing instance of type BasicActivity (e.g. x.new A() where x is an instance of BasicActivity). 描述: 在BasicActivity.java中写了一个public class 的内部类,在另一个java文件

Java中出现No enclosing instance of type XXX is accessible问题

Java编写代码过程中遇到了一个问题,main方法中创建内部类的实例时,编译阶段出现错误,查看错误描述: Multiple markers at this line - The value of the local variable test is not used - No enclosing instance of type StaticCallDynamic is accessible. Must qualify the allocation with an enclosing insta

java解决 No enclosing instance of type XXX is accessible的问题

有些时候我们要把Activity的一些实现类移到java类里来实现,比如把写以下两个类: 在LifeCircle这个类中: public class LifeCircle { public class Mybroadcast extends BroadcastReceiver { @Override public void onReceive(Context context, Intent intent) { } } } 如果在Activity这样去new: public class Setti

Java编译时出现No enclosing instance of type XXX is accessible.

今天在编译Java程序的时候出现以下错误: No enclosing instance of type Main is accessible. Must qualify the allocation with an enclosing instance of type Main (e.g. x.new A() where x is an instance of Main). 我原来编写的源代码是这样的: public class Main {class Dog //定义一个“狗类”{privat

No enclosing instance of type E is accessible. Must qualify the allocation with an enclosing

package com.thread; public class Thread01 { public class Thread1 extends Thread{ private String name; public Thread1(String name){ this.name = name; } public void run() { for (int i = 0; i < 5; i++) { System.out.println(name+"运行:"+i); try { s

Java错误No enclosing instance of type Hidden is accessible

今天在写一个小的程序时出现No enclosing instance of type Hidden is accessible. Must qualify the allocation with an enclosing instance of type Hidden (e.g. x.new A() where x is an instance of Hidden).的错误,寻找了很长时间,终于解决了. 我的程序是: public class Hidden { class Father{ /*p