Sqlserver数据库分页查询一直是Sqlserver的短板,闲来无事,想出几种方法,假设有表ARTICLE,字段ID、YEAR...(其他省略),数据53210条(客户真实数据,量不大),分页查询每页30条,查询第1500页(即第45001-45030条数据),字段ID聚集索引,YEAR无索引,Sqlserver版本:2008R2
第一种方案、最简单、普通的方法:
SELECT TOP 30 * FROM ARTICLE WHERE ID NOT IN (SELECT TOP 45000 ID FROM ARTICLE ORDER BY YEAR DESC, ID DESC) ORDER BY YEAR DESC,ID DESC
第二种方案:
代码如下:
SELECT * FROM (SELECT TOP 30 * FROM (SELECT TOP 45030 * FROM ARTICLE ORDER BY YEAR DESC, ID DESC) f ORDER BY f.YEAR ASC, f.ID DESC) s ORDER BY s.YEAR DESC,s.ID DESC
平均查询100次所需时间:138S
第三种方案:
代码如下:
SELECT * FROM ARTICLE w1, ( SELECT TOP 30 ID FROM ( SELECT TOP 50030 ID, YEAR FROM ARTICLE ORDER BY YEAR DESC, ID DESC ) w ORDER BY w.YEAR ASC, w.ID ASC ) w2 WHERE w1.ID = w2.ID ORDER BY w1.YEAR DESC, w1.ID DESC
平均查询100次所需时间:21S
第四种方案:
代码如下:
SELECT * FROM ARTICLE w1 WHERE ID in ( SELECT top 30 ID FROM ( SELECT top 45030 ID, YEAR FROM ARTICLE ORDER BY YEAR DESC, ID DESC ) w ORDER BY w.YEAR ASC, w.ID ASC ) ORDER BY w1.YEAR DESC, w1.ID DESC
平均查询100次所需时间:20S
第五种方案:
代码如下:
SELECT w2.n, w1.* FROM ARTICLE w1, (SELECT TOP 50030 row_number() OVER (ORDER BY YEAR DESC, ID DESC) n, ID FROM ARTICLE ) w2 WHERE w1.ID = w2.ID AND w2.n > 50000 ORDER BY w2.n ASC
平均查询100次所需时间:15S
查询第1000-1030条记录
第一种方案:
代码如下:
SELECT TOP 30 * FROM ARTICLE WHERE ID NOT IN(SELECT TOP 1000 ID FROM ARTICLE ORDER BY YEAR DESC, ID DESC) ORDER BY YEAR DESC,ID DESC
平均查询100次所需时间:80s
第二种方案:
代码如下:
SELECT * FROM ( SELECT TOP 30 * FROM (SELECT TOP 1030 * FROM ARTICLE ORDER BY YEAR DESC, ID DESC) f ORDER BY f.YEAR ASC, f.ID DESC) s ORDER BY s.YEAR DESC,s.ID DESC
平均查询100次所需时间:30S
第三种方案:
代码如下
SELECT * FROM ARTICLE w1, ( SELECT TOP 30 ID FROM ( SELECT TOP 1030 ID, YEAR FROM ARTICLE ORDER BY YEAR DESC, ID DESC ) w ORDER BY w.YEAR ASC, w.ID ASC ) w2 WHERE w1.ID = w2.ID ORDER BY w1.YEAR DESC, w1.ID DESC
平均查询100次所需时间:12S
第四种方案:
代码如下:
SELECT * FROM ARTICLE w1 WHERE ID in ( SELECT top 30 ID FROM ( SELECT top 1030 ID, YEAR FROM ARTICLE ORDER BY YEAR DESC, ID DESC ) w ORDER BY w.YEAR ASC, w.ID ASC ) ORDER BY w1.YEAR DESC, w1.ID DESC
平均查询100次所需时间:13S
第五种方案:
代码如下:
SELECT w2.n, w1.* FROM ARTICLE w1,(SELECT TOP 1030 row_number() OVER (ORDER BY YEAR DESC, ID DESC) n, ID FROM ARTICLE) w2 WHERE w1.ID = w2.ID AND w2.n > 1000 ORDER BY w2.n ASC
平均查询100次所需时间:14S
由此可见在查询页数靠前时,效率3>4>5>2>1,页码靠后时5>4>3>1>2,再根据用户习惯,一般用户的检索只看最前面几页,因此选择3 4 5方案均可,若综合考虑方案5是最好的选择,但是要注意SQL2000不支持row_number()函数,由于时间和条件的限制没有做更深入、范围更广的测试,有兴趣的
第六种方案:
代码如下:
SELECT* FROM (SELECT TOP 1030 row_number() OVER (ORDER BY YEAR DESC, ID DESC) n, * FROM ARTICLE) w2 WHERE w2.n > 1000
效率和第五种方案差不多
原文地址:https://www.cnblogs.com/caiyt/p/11797644.html
时间: 2024-10-07 18:13:56