Given a text file file.txt
that contains list of phone numbers (one per line), write a one liner bash script to print all valid phone numbers.
You may assume that a valid phone number must appear in one of the following two formats: (xxx) xxx-xxxx or xxx-xxx-xxxx. (x means a digit)
You may also assume each line in the text file must not contain leading or trailing white spaces.
For example, assume that file.txt
has the following content:
987-123-4567 123 456 7890 (123) 456-7890
Your script should output the following valid phone numbers:
987-123-4567 (123) 456-7890
考察Linux查找文本的操作,主要是命令与正则表达式
# Read from the file file.txt and output all valid phone numbers to stdout. # No.1 grep -e "^[0-9]\\{3\\}-[0-9]\\{3\\}-[0-9]\\{4\\}$" -e "^([0-9]\\{3\\}) [0-9]\\{3\\}-[0-9]\\{4\\}$" file.txt # No.2 grep -e "^\\([0-9]\\{3\\}-\\|([0-9]\\{3\\}) \\)[0-9]\\{3\\}-[0-9]\\{4\\}$" file.txt
原文地址:https://www.cnblogs.com/immjc/p/8207207.html
时间: 2024-11-03 12:10:09