OC-数组类-几道练习

3.有两个字符串@"I am a good girl";@"You are a bad boy"; 将这两个字符串单词,交叠,形成系的字符串 @"I You am are a a good bad girl boy"

 1 int main(int argc, const char * argv[]) {
 2     @autoreleasepool {
 3          char str1[100] = {};
 4         char str2[100] = {};
 5         //按格式输入：%[^\n] 解释：表示除了‘\n‘所有字符都被视为字符串的一部分,】‘\n‘：读取到‘\n‘时，为第二个字符串输入
 6         scanf("%[^\n]\n%[^\n]",str1,str2);
 7         NSString *string1 = [NSString stringWithUTF8String:str1];
 8         NSString *string2 = [NSString stringWithUTF8String:str2];
 9
10         NSLog(@"string1 = %@",string1);
11         NSLog(@"string2 = %@",string2);
12
13         NSArray *array1 = [string1 componentsSeparatedByString:@" "];
14         NSArray *array2 = [string2 componentsSeparatedByString:@" "];
15         NSUInteger len1 = [array1 count];
16         NSUInteger len2 = [array2 count];
17         NSArray *array = [[NSArray alloc]init];
18         NSUInteger len = len1<len2?len1:len2;
19         for (int i=0; i<len; i++) {
20             array = [array arrayByAddingObject:[array1 objectAtIndex:i]];
21             array = [array arrayByAddingObject:[array2 objectAtIndex:i]];
22         }
23
24         //获取比较长的字符串的剩余子串
25         NSArray *subArray = [NSArray array];
26         if (len1 > len2) {
27             subArray = [array1 subarrayWithRange:NSMakeRange(len, len1-len)];
28         }else{
29             subArray = [array2 subarrayWithRange:NSMakeRange(len, len2-len)];
30         }
31
32         NSArray *resArray = [array arrayByAddingObjectsFromArray:subArray];
33         NSString *resString = [resArray componentsJoinedByString:@" "];
34         NSLog(@"%@",resString);
35     }
36 }    

2.对称字符串

传入一个字符串,将这个字符串组合成一个新的对称字符串返回

例如:

传入:@"I love you Mery"

返回:@"I love you Mery Mery you love I"

 1 int main(int argc, const char * argv[]) {
 2     @autoreleasepool {
 3
 4         //以字符串整体进行分割
 5         NSString *src = @"I love you Mery";
 6         NSArray *array = [src componentsSeparatedByString:@" "];
 7         NSArray *retArray = [[NSArray alloc] initWithArray:array];
 8         //1.method:第一种for循环遍历
 9         /*
10         NSUInteger len = [array count];
11         for (NSInteger i=len-1; i>=0; i--) {
12             retArray = [retArray arrayByAddingObject:[array objectAtIndex:i]];
13         }
14         NSString *resString = [retArray componentsJoinedByString:@" "];
15         NSLog(@"%@",resString);
16          */
17         //2.第二种枚举器遍历
18         /*
19         NSEnumerator *reverseEnumerator = [[NSEnumerator alloc] init];
20         reverseEnumerator = [array reverseObjectEnumerator];
21         id obj = nil;
22         while (obj = [reverseEnumerator nextObject]) {
23             retArray = [retArray arrayByAddingObject:obj];
24         }
25         NSString *resString = [retArray componentsJoinedByString:@" "];
26         NSLog(@"%@",resString);
27          */
28     }
29 }