python简单的交互式操作，实例
方法一：
#!/usr/bin/env python
#encoding:utf8
# Filename:interactive.py
name= raw_input("please input your name:")
passwd= raw_input("please input your passwd:")
count = 0
temp = 0
if name == ‘liu‘:
if passwd == ‘123‘:
print ‘welcome login!‘
else:
for i in range(4):
count += i
if passwd == ‘123‘:
print ‘welcome login‘
break
if ( count == 3 ):
print "you passwd locked!"
else:
passwd= raw_input("please reset input your passwd:")
elif passwd == ‘123‘:
print ‘true‘,passwd
for x in range(4):
temp += x
print ‘varlue:‘,temp
if name == ‘liu‘:
print ‘welcome login‘
break
if ( temp == 3 ):
print "you name locked"
break
else:
name= str(raw_input("please reset input your name:"))
else:
print ‘name,passwd error!:‘
#####################################################################################
方法二：
#!/usr/bin/python
# Filename:interactive_1.py
i = 1
while 1:
Name = raw_input("please input your name:")
Email = raw_input("please input your email:")
QQ = int(raw_input("please input your qq:"))
s2 = "{Name:[Email,QQ]}"
s3 = eval(s2)
# if s3.has_key(Name):
s3 = dict(s3.items() + s3.items())
print i
i += 1
if i > 3:
break
#s3(s3.items()) += s3(s3.items())
# else:
# raw_input("First please input your information! Enter")