列表的添加和删除

Python 2.7.10 (default, Oct 14 2015, 16:09:02)
[GCC 5.2.1 20151010] on linux2
Type "copyright", "credits" or "license()" for more information.
>>> assert 3>4

Traceback (most recent call last):
  File "<pyshell#0>", line 1, in <module>
    assert 3>4
AssertionError
>>> assert 4>3
>>> range(4,5)
[4]
>>> member=["nihao","hello"]
>>> member
[‘nihao‘, ‘hello‘]
>>> member
[‘nihao‘, ‘hello‘]
>>> empty=[]
>>> empty
[]
>>> a=["nihao",1,[2,3,4]]
>>> a
[‘nihao‘, 1, [2, 3, 4]]
>>> num=[1,2,3]
>>> num
[1, 2, 3]
>>> len(num)
3
>>> num.append(4) #插入元素
>>> num
[1, 2, 3, 4]
>>> len(num)
4
>>> num.append("nizhi")
>>> len(num)
5
>>> num
[1, 2, 3, 4, ‘nizhi‘]
>>> num.append(5,6)　　#不能插入两个元素

Traceback (most recent call last):
  File "<pyshell#19>", line 1, in <module>
    num.append(5,6)
TypeError: append() takes exactly one argument (2 given)
>>> num.extend([5,6])　　#用extend可以插入多个元素
>>> num
[1, 2, 3, 4, ‘nizhi‘, 5, 6]
>>> len(num)
7
>>> num.insert(0,10)　　#在中间进行插入元素
>>> num
[10, 1, 2, 3, 4, ‘nizhi‘, 5, 6]
>>> len(num)
8
>>> num[0]
10
>>> num[5]
‘nizhi‘
>>> print(num[5])
nizhi
>>> tmp=num[0]
>>> num[0]=num[7]
>>> num[7]=tmp
>>> num
[6, 1, 2, 3, 4, ‘nizhi‘, 5, 10]
>>> len(num)
8
>>> num.remove("nizhi")　　#删除
>>> num
[6, 1, 2, 3, 4, 5, 10]
>>> member.remove(11)

Traceback (most recent call last):
  File "<pyshell#36>", line 1, in <module>
    member.remove(11)
ValueError: list.remove(x): x not in list
>>> del num[0]　#　删除某个
>>> num
[1, 2, 3, 4, 5, 10]
>>> num.pop() #从最后删除，有返回值
10
>>> tmp=num.pop()#可以用变量来承接一下poop出来的返回值
>>> tmp
5
>>> num.pop(0)
1
>>> num
[2, 3, 4]
>>> 

列表切片   [:]取出中间的某一段元素切片，如果不加上，默认就是边界

 1 >>> a=[1,2,3,4,5,6]
 2 >>> a
 3 [1, 2, 3, 4, 5, 6]
 4 >>> a[1:3]
 5 [2, 3]
 6 >>> a[:4]
 7 [1, 2, 3, 4]
 8 >>> a[1:]
 9 [2, 3, 4, 5, 6]
10 >>> a[:]
11 [1, 2, 3, 4, 5, 6]
12 >>> tmp_a=a
13 >>> tmp_a
14 [1, 2, 3, 4, 5, 6]
15 >>> tmp_b=a[:]
16 >>> tmp_b
17 [1, 2, 3, 4, 5, 6]
18 >>>