该类模板实现了一个二叉树的模板类,采用二叉链表实现。
定义二叉树节点类,采用二叉链表实现。
///////////////////////// #include <iostream> #include <cstdlib> #include <stack> #include <deque> using namespace std; template<class T> struct BinTreeNode //二叉树节点类的定义,使用二叉链表 { T data; BinTreeNode<T> *leftChild, *rightChild; BinTreeNode():leftChild(NULL),rightChild(NULL){} BinTreeNode(T x,BinTreeNode<T> *l=NULL,BinTreeNode<T> *r=NULL):data(x),leftChild(l),rightChild(r){} };
二叉树的模板类实现如下:可进行相应的功能扩展。
接口部分:
template<class T> class BinaryTree//二叉树的模板类 { public: BinaryTree():root(NULL){} BinaryTree(char x):root(NULL),RefValue(x){} BinaryTree(const BinaryTree<T>& rhs){root=copy(rhs.root);}//copy构造函数 BinaryTree<T>& operator=(const BinaryTree<T>& rhs);//copy 赋值运算符;析构+copy构造函数 ~BinaryTree(){destroy(root);}//析构函数 bool isEmpty()const{return root!=NULL?false:true;} BinTreeNode<T>* leftChild(BinTreeNode<T>* current)const{return current!=NULL?current->leftChild:NULL;} BinTreeNode<T>* rightChild(BinTreeNode<T>* current)const{return current!=NULL?current->rightChild:NULL;} BinTreeNode<T>* parent(BinTreeNode<T>* current)const{return (root==NULL || current==root)?NULL:parent(root,current);}//寻找其父节点 BinTreeNode<T>* getRoot()const{return root;} void inOrder(void (*visit)(BinTreeNode<T> *p)){inOrder(root,visit);}//中序递归遍历 void preOrder(void (*visit)(BinTreeNode<T> *p)){preOrder(root,visit);}//前序递归 void postOrder(void (*visit)(BinTreeNode<T> *p)){postOrder(root,visit);}//后序递归 void levelOrder(void (*visit)(BinTreeNode<T> *p));//使用队列的层次遍历 int size()const {return size(root);}//使用后序递归遍历求节点个数 int height()const {return height(root);}//使用后序递归遍历求二叉树的高度 protected: BinTreeNode<T> *root; char RefValue;//数据输入停止标志 void destroy(BinTreeNode<T>* subTree);//递归删除二叉树节点,后序遍历删除 BinTreeNode<T>* copy(const BinTreeNode<T> *orignode);//copy构造;前序 BinTreeNode<T>* parent(BinTreeNode<T>* subTree,BinTreeNode<T>* current)const;//返回父节点 void traverse(BinTreeNode<T>* subTree,ostream& out)const;//按前序方式遍历输出每个节点的值 void createBinTree(istream& in,BinTreeNode<T>* & subTree);//采用广义表表示的二叉树创建方法 void inOrder(BinTreeNode<T> *subTree,void (*visit)(BinTreeNode<T> *p));//中序遍历 void preOrder(BinTreeNode<T> *subTree,void (*visit)(BinTreeNode<T> *p));//前序遍历 void postOrder(BinTreeNode<T> *subTree,void (*visit)(BinTreeNode<T> *p));//后序遍历 int size(BinTreeNode<T> *subTree)const;//使用后序递归遍历求节点个数 int height(BinTreeNode<T> *subTree)const;//使用后序递归遍历求二叉树的高度 friend ostream& operator<< <T>(ostream& out,const BinaryTree<T>& rhs);//add <T> 前序输出二叉树 friend istream& operator>> <T>(istream& in, BinaryTree<T>& rhs); //add <T> 采用广义表表示方式创建二叉树 };
相应成员函数的具体实现:
template<class T> void BinaryTree<T>::destroy(BinTreeNode<T>* subTree) { if(subTree!=NULL){ destroy(subTree->leftChild); destroy(subTree->rightChild); delete subTree; } } template<class T> BinTreeNode<T>* BinaryTree<T>::parent(BinTreeNode<T>* subTree,BinTreeNode<T>* current)const { if(subTree==NULL) return NULL; if(subTree->leftChild==current || subTree->rightChild==current) return subTree; BinTreeNode<T>* p; if((p=parent(subTree->leftChild,current))!=NULL) return p else return parent(subTree->rightChild,current); } template<class T> void BinaryTree<T>::traverse(BinTreeNode<T>* subTree,ostream& out)const { if(subTree!=NULL){ out<<subTree->data<<" "; traverse(subTree->leftChild,cout); traverse(subTree->rightChild,out); } } template<class T> void BinaryTree<T>::createBinTree(istream& in,BinTreeNode<T>* & subTree) { stack<BinTreeNode<T>* > s; subTree=NULL; BinTreeNode<T> *p,*t; unsigned int k; T ch; in>>ch;//虽然是模板类,但是目前只支持字符型,不然会报错 while(ch!=RefValue){ switch(ch){ case ‘(‘: s.push(p);k=1;break; case ‘)‘: s.pop();break; case ‘,‘: k=2;break; default: p=new BinTreeNode<T>(ch); if(subTree==NULL) subTree=p; else if(k==1) {t=s.top();t->leftChild=p;} else {t=s.top();t->rightChild=p;} } in>>ch; } } template<class T> ostream& operator<<(ostream& out,const BinaryTree<T>& rhs) { rhs.traverse(rhs.root,out); out<<endl; return out; } template<class T> istream& operator>>(istream& in, BinaryTree<T>& rhs) { rhs.createBinTree(in,rhs.root); return in; } template<class T> void BinaryTree<T>::inOrder(BinTreeNode<T> *subTree,void (*visit)(BinTreeNode<T> *p)) { if(subTree!=NULL){ inOrder(subTree->leftChild,visit); visit(subTree); inOrder(subTree->rightChild,visit); } } template<class T> void BinaryTree<T>::preOrder(BinTreeNode<T> *subTree,void (*visit)(BinTreeNode<T> *p)) { if(subTree!=NULL){ visit(subTree); inOrder(subTree->leftChild,visit); inOrder(subTree->rightChild,visit); } } template<class T> void BinaryTree<T>::postOrder(BinTreeNode<T> *subTree,void (*visit)(BinTreeNode<T> *p)) { if(subTree!=NULL){ inOrder(subTree->leftChild,visit); inOrder(subTree->rightChild,visit); visit(subTree); } } template<class T> int BinaryTree<T>::size(BinTreeNode<T> *subTree)const { if(subTree==NULL) return 0; else return 1+size(subTree->leftChild)+size(subTree->rightChild); } template<class T> int BinaryTree<T>::height(BinTreeNode<T> *subTree)const { if(subTree==NULL) return 0; else{ int i=height(subTree->leftChild); int j=height(subTree->rightChild); return (i>j)?i+1:j+1; } } template<class T> BinTreeNode<T>* BinaryTree<T>::copy(const BinTreeNode<T> *orignode) { if(orignode==NULL) return NULL; BinTreeNode<T> *temp=new BinTreeNode<T>; temp->data=orignode->data; temp->leftChild=copy(orignode->leftChild); temp->rightChild=copy(orignode->rightChild); return temp; } template<class T> BinaryTree<T>& BinaryTree<T>::operator=(const BinaryTree<T>& rhs) { this->destroy(this->root); this->root=copy(rhs.root); return *this; } template<class T> void BinaryTree<T>::levelOrder(void (*visit)(BinTreeNode<T> *p)) { deque<BinTreeNode<T>* > dq; BinTreeNode<T> *p=root; dq.push_back(p); while(!dq.empty()){ p=dq.front(); visit(p); dq.pop_front(); if(p->leftChild!=NULL) dq.push_back(p->leftChild); if(p->rightChild!=NULL) dq.push_back(p->rightChild); } }
测试函数:
int main(int argc, char* argv[]) { BinaryTree<char> b(‘#‘); cin>>b; cout<<b<<endl; //b.levelOrder(NULL); //BinaryTree<char> a(‘#‘); //cin>>a; //cout<<a<<endl; // b=a; //cout<<b<<endl; //BinaryTree<char> a=b; //cout<<a<<endl; //cout<<b.size()<<endl; //cout<<b.isEmpty()<<endl; //cout<<b.height()<<endl; system("pause"); return 0; }
测试结果:
a(b(c,d),e(f,g))#
a b c d e f g
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时间: 2024-10-11 20:36:38