剑指offer python版 替换空格

题目描述: 请实现一个函数,将一个字符串中的空格替换成"%20".例如,当字符串为We Are Happy.则经过替换之后的字符串为We%20Are%20Happy. 解题思路: 本题中需要注意,新的字符串的长度要比旧的字符串长度长,这意味着,从前往后替换的话,每更换一次,后面的字符就要向后移动.因此,在替换的过程中需要考虑到时间复杂度和空间复杂度的问题. public class Solution { public String replaceSpace(StringBuffer s

题目描述 请实现一个函数,将一个字符串中的空格替换成"%20".例如,当字符串为We Are Happy.则经过替换之后的字符串为We%20Are%20Happy. 1 public class Solution { 2 public String replaceSpace(StringBuffer str) { 3 int startIndex; 4 while((startIndex = str.indexOf(" ")) >= 0){ 5 str.rep

请实现一个函数,将一个字符串中的空格替换成"%20".例如,当字符串为We Are Happy.则经过替换之后的字符串为We%20Are%20Happy. class Solution { public: void replaceSpace(char *str,int length) { int newlength = 0, blank_number = 0, str_len = 0, tail = 0; for(str_len = 0; str[str_len] != '\0'; s

题目描述 请实现一个函数,将一个字符串中的每个空格替换成"%20".例如,当字符串为We Are Happy.则经过替换之后的字符串为We%20Are%20Happy. 时间限制:C/C++ 1秒,其他语言2秒 空间限制:C/C++ 32M,其他语言64M public class Solution { public static String replaceSpace(StringBuffer str) { //健壮性判断 if (str == null) { return null

def find_integer(matrix, num): """ :param matrix: [[]] :param num: int :return: bool """ if not matrix: return False rows, cols = len(matrix), len(matrix[0]) row, col = rows - 1, 0 while row >= 0 and col <= cols - 1: if

class singleTon(object): def __init__(self,x): self.val=x single2=singleTon(2) a=single2 b=single2 print(a==b) print(a.val) a.val=334 print(b.val) 原文地址:https://www.cnblogs.com/xzm123/p/9847787.html

class ListNode(object): def __init__(self,x): self.val=x self.next=None class Link(object): def __init__(self,values=None): self.nodes=self.set_link(values) if values else None def get_link(self): return self.nodes def set_link(self,values): if not v

class ListNode(object): def __init__(self,x): self.val=x self.next=None class Link(object): def __init__(self,values=None): self.nodes=self.set_link(values) if values else None def get_link(self): return self.nodes def set_link(self,values): if not v

def aa(matrix): rows=len(matrix) cols=len(matrix[0]) start=0 ret=[] while start*2 <rows and start*2<cols: bb(matrix,rows,cols,start,ret) start +=1 return ret def bb(matrix,rows,cols,start,ret): row=rows-start-1 col=cols-start-1 for c in range(start,