1,叠加多个装饰器
1),加载顺序(outter函数的调用顺序):自下而上
2),执行顺序(wrapper函数的执行顺序):自上而下
def outter1(func1): #func1=wrapper2的内存地址 print(‘加载了outter1‘) def wrapper1(*args,**kwargs): print(‘执行了wrapper1‘) res1=func1(*args,**kwargs) return res1 return wrapper1 def outter2(func2): #func2=wrapper3的内存地址 print(‘加载了outter2‘) def wrapper2(*args,**kwargs): print(‘执行了wrapper2‘) res2=func2(*args,**kwargs) return res2 return wrapper2 def outter3(func3): # func3=最原始的那个index的内存地址 print(‘加载了outter3‘) def wrapper3(*args,**kwargs): print(‘执行了wrapper3‘) res3=func3(*args,**kwargs) return res3 return wrapper3 @outter1 # outter1(wrapper2的内存地址)======>index=wrapper1的内存地址 @outter2 # outter2(wrapper3的内存地址)======>wrapper2的内存地址 @outter3 # outter3(最原始的那个index的内存地址)===>wrapper3的内存地址 def index(): print(‘from index‘)
import time #时间统计函数 def timmer(func): def wrapper(*args, **kwargs): start = time.time() res = func(*args, **kwargs) stop = time.time() print(‘run %s‘ % (stop - start)) return res return wrapper #账户登录验证函数 def duth(func): def wrapper(*args, **kwargs): name = input(‘please input your name:‘) pwd = input(‘please input your password:‘) if name == ‘egom‘ and pwd == ‘123‘: print(‘login successful‘) res = func(*args, **kwargs) return res else: print(‘your name or password error‘) return wrapper @timmer @duth #装饰器将下面函数的函数名当做参数,然后将运行的结果在赋值给原函数index # def index(): time.sleep(1) print(‘from index‘) index()
2,有参装饰器
current_user = {‘user‘:None} def duth(engine=‘file‘): def outter(func): def wrapper(*args,**kwargs): #确认current字典内是否有存在的数据 if current_user[‘user‘] is not None: res = func(*args,**kwargs) return res name = input(‘your name :‘).strip() password = input(‘your password :‘).strip() #基于‘file‘文件认证 if engine == ‘file‘: if name == ‘egon‘ and password == ‘123‘: print(‘login successful‘) current_user[‘user‘]=name res=func(*args,**kwargs) return res else: print(‘your name or password error‘) elif engine == ‘mysql‘ : print(‘基于mysql认证‘) elif engine == ‘ldap‘ : print(‘基于ldap认证‘) else: print(‘hello‘) return wrapper return outter
3,三元表达式
def max2(x,y): if x > y: return x else: return y res=max2(10,20) x=10 y=20 # res=x if x > y else y # print(res) res=‘OK‘ if False else ‘No‘ print(res)
4,生成式
列表生成式
l=[] for i in range(10): if i > 4: l.append(i**2) l=[i**2 for i in range(10) if i > 4] print(l)
names=[‘egon‘,‘alex_sb‘,‘kevin_sb‘,‘hxx_sb‘,‘cxx_sb‘] sbs=[] for name in names: if name.endswith(‘sb‘): sbs.append(name) sbs=[name.upper() for name in names if name.endswith(‘sb‘)]
字典生成器
res={i:i**2 for i in range(10) if i > 3} print(res) print({i for i in ‘hello‘})
5,匿名函数
原文地址:https://www.cnblogs.com/kp1995/p/10046610.html
时间: 2024-10-22 07:56:05