https://leetcode.com/problems/second-highest-salary/
Second Highest Salary
Write a SQL query to get the second highest salary from the Employee
table.
+----+--------+ | Id | Salary | +----+--------+ | 1 | 100 | | 2 | 200 | | 3 | 300 | +----+--------+
For example, given the above Employee table, the second highest salary is 200
. If there is no second highest salary, then the query should return null
.
首先MySQL不支持top语法,要用limit代替。
select Salary from Employee order by Salary desc limit 1,1
这样写的话如果不存在,select出来是空,题目需要是null(掀桌。
Input: {"headers": {"Employee": ["Id", "Salary"]}, "rows": {"Employee": [[1, 100]]}} Output: {"headers": ["Salary"], "values": []} Expected: {"headers": ["SecondHighestSalary"], "values": [[null]]}
于是就需要在外面再包一层。为什么要加distinct呢,是因为不加过不了这个case:
+----+--------+ | Id | Salary | +----+--------+ | 1 | 100 | | 2 | 100 | +----+--------+ 最终解法:
select (select distinct Salary from Employee order by Salary desc limit 1,1) as Salary;
时间: 2024-10-19 19:52:38