集训第四周(高效算法设计)A题 Ultra-QuickSort

原题poj 2299:http://poj.org/problem?id=2299

题意,给你一个数组,去统计它们的逆序数,由于题目中说道数组最长可达五十万,那么O(n^2)的排序算法就不要再想了,接下来的选择是快排,归并,看你喜欢了

这里列出归并的解法:

#include"iostream"
using namespace std;

const int maxn=500000+10;

int T[maxn];
int a[maxn];

long long sum;

void merge_sort(int *a,int x,int y,int *T)
{
    if(y-x>1)
    {
        int m=x+(y-x)/2;
        int p=x,q=m,i=x;
        merge_sort(a,x,m,T);
        merge_sort(a,m,y,T);
        while(p<m||q<y)
        {
            if(q>=y||(p<m&&a[p]<a[q])) T[i++]=a[p++];
            else {sum+=m-p;T[i++]=a[q++];}
        }
        for(int i=x;i<y;i++) a[i]=T[i];
    }
}
int main()
{
    int n;
    while(cin>>n&&n)
    {
        sum=0;
        for(int i=0;i<n;i++) cin>>a[i];
        merge_sort(a,0,n,T);
     /*   for(int i=0;i<n;i++) cout<<a[i]<<‘ ‘;
        cout<<endl;*/
        cout<<sum<<endl;
    }
    return 0;
}
时间: 2024-08-01 18:20:14

集训第四周(高效算法设计)A题 Ultra-QuickSort的相关文章

集训第四周(高效算法设计)N题 (二分查找优化题)

原题:poj3061 题意:给你一个数s,再给出一个数组,要求你从中选出m个连续的数,m越小越好,且这m个数之和不小于s 这是一个二分查找优化题,那么区间是什么呢?当然是从1到数组长度了.比如数组长度为10,你先找5,去枚举每一个区间为5的连续的数,发现存在这样的数,那么就可以继续往左找,反之则往右找,直到左右区间重合,即为正确答案,(有可能是右区间小于左区间,所以每次都应该求区间中点值) #include"iostream" #include"set" #incl

集训第四周(高效算法设计)M题 (扫描法)

原题:UVA11078 题意:给你一个数组,设a[],求一个m=a[i]-a[j],m越大越好,而且i必须小于j 怎么求?排序?要求i小于j呢.枚举?只能说超时无上限.所以遍历一遍数组,设第一个被减数为a[0],之后遇到比a[0]大的数就更新它,再拿这个被减数去减数组中的每一个元素,同时也要不断地更新这个m值. #include"iostream" #include"set" #include"cstring" #include"cst

集训第四周(高效算法设计)P题 (构造题)

Description There are N<tex2html_verbatim_mark> marbles, which are labeled 1, 2,..., N<tex2html_verbatim_mark> . The N<tex2html_verbatim_mark> marbles are put in a circular track in an arbitrary order. In the top part of the track there

集训第四周(高效算法设计)O题 (构造题)

A permutation on the integers from 1 to n is, simply put, a particular rearrangement of these integers. Your task is to generate a given permutation from the initial arrangement 1, 2, 3, . . . , n using only two simple operations. •  Operation 1: You

集训第四周(高效算法设计)I题 (贪心)

Description Shaass has n books. He wants to make a bookshelf for all his books. He wants the bookshelf's dimensions to be as small as possible. The thickness of the i-th book is ti and its pages' width is equal to wi. The thickness of each book is ei

集训第四周(高效算法设计)L题 (背包贪心)

Description John Doe is a famous DJ and, therefore, has the problem of optimizing the placement of songs on his tapes. For a given tape and for each song on that tape John knows the length of the song and the frequency of playing that song. His probl

集训第四周(高效算法设计)K题 (滑窗问题)

UVA 11572 唯一的雪花 题意:给你从1到n的数组,要求求得其中的最长连续不重复子序列,经典的滑窗问题,方法是维护一个窗口,设置左框和右框,然后不断的进行维护和更新 方法一: #include"iostream" #include"set" #include"cstring" #include"cstdio" #include"algorithm" using namespace std; const

集训第四周(高效算法设计)J题 (中途相遇法)

Description The SUM problem can be formulated as follows: given four lists A, B, C, D<tex2html_verbatim_mark> of integer values, compute how many quadruplet (a, b, c, d ) AxBxCxD<tex2html_verbatim_mark> are such that a + b + c + d = 0<tex2h

集训第四周(高效算法设计)G题 (贪心)

G - 贪心 Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Description Simon and Garfunkel Corporation (SG Corp.) is a large steel-making company with thousand of customers. Keeping the customer satisfied is one of th