快速找到一条记录所在的页码

算出这条记录所在的rowNum，rowNum是连续的，再根据rowNum算出这条记录所在的页码。

public int getPageNoByBackId(int noteId,int backId,int pageSize) {
	StringBuilder sql = new StringBuilder();
	sql.append(" select num from ( \n");
	sql.append("select ROW_NUMBER() over(order by backId) as num,backId  \n");
	sql.append("from forum..f_topic_reply where noteId=? \n");
	sql.append(") a where a.backId =? \n");

	log.debug(sql.toString());
	int rowNum = 0;
	DB db = null;
	try {
		db = getGkDB();
		rowNum = db.queryForInt(sql.toString(), new Object[] {noteId,backId});
	} catch (Exception e) {
		log.error(e);
	}finally{
		if(db!=null)db.close();
	}
	int pageNum = 0;
	if(rowNum>0){
		if(rowNum%pageSize==0){
			pageNum=rowNum/pageSize;
		}else{
			pageNum=rowNum/pageSize+1;
		}
	}
	return pageNum;
}

如果一个链接里有锚点，跳转的时候用window.location打开不起作用，但在document.location中打开是可以的