SimpleAdapter(Context context, List<? extends Map<String, ?>> data, int resource, String[] from, int[] to)
参数context:上下文,比如this。关联SimpleAdapter运行的视图上下文
参数data:Map列表,列表要显示的数据,它是包含Map类型的元素的List集合,并且要求Map的键必须是String 类型的。
参数resource:ListView单项布局文件的Id,这个布局就是你自定义的布局了,你想显示什么样子的布局都在这个布局中。这个布局中必须包括了to中定义的控件id
参数 from:一个被添加到Map上关联每一个项目列名称的列表,数组里面是列名称。
参数 to:是一个int数组,数组里面的id是自定义布局中各个控件的id,需要与上面的from一一对应。
下面举个例子说明:
自定义布局显示本地资源;列表项的单项显示格式,定义main.xml文件,如下:
<?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="horizontal" > <ImageView android:id="@+id/img" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_margin="3px" /> <LinearLayout android:layout_width="fill_parent" android:layout_height="wrap_content" android:orientation="vertical" > <TextView android:id="@+id/title" android:layout_width="fill_parent" android:layout_height="wrap_content" android:textSize="16sp" /> <TextView android:id="@+id/info" android:layout_width="fill_parent" android:layout_height="wrap_content" android:textSize="10sp" /> </LinearLayout> </LinearLayout> 如果直接继承ListAcitivty,则不需要自定义ListView
public class DemoActivity extends ListActivity { /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); SimpleAdapter adapter = new SimpleAdapter(this, getData(), R.layout.main, new String[] { "img", "title", "info" }, new int[] { R.id.img, R.id.title, R.id.info }); setListAdapter(adapter); }
private List<Map<String, Object>> getData() { List<Map<String, Object>> list = new ArrayList<Map<String, Object>>(); Map<String, Object> map = new HashMap<String, Object>(); map.put("img", R.drawable.ic_icon1); map.put("title", "zhangsan"); map.put("info", "asd"); list.add(map); map = new HashMap<String, Object>(); map.put("img", R.drawable.ic_icon2); map.put("title", "wangwu"); map.put("info", "sadf"); list.add(map); map = new HashMap<String, Object>(); map.put("img", R.drawable.e04b); map.put("title", "zhaoliu"); map.put("info", "fegg"); list.add(map); map = new HashMap<String, Object>(); map.put("img", R.drawable.e04e); map.put("title", "dog"); map.put("info", "efdfdg"); list.add(map); map = new HashMap<String, Object>(); map.put("img", R.drawable.e11a); map.put("title", "hello"); map.put("info", "every thing"); list.add(map); map = new HashMap<String, Object>(); map.put("img", R.drawable.e11d); map.put("title", "world"); map.put("info", "hello world"); list.add(map); return list; } }
如果自定义ListView而不是继承ListActivity需要如下实现,定义一个mylist.xml,在ListView中可以定义其他属性。
<?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="match_parent" android:layout_height="match_parent" android:orientation="vertical" > <ListView android:id="@+id/listview" android:layout_width="fill_parent" android:layout_height="wrap_content" ></ListView> </LinearLayout>
如此,DemoActivity中的代码就要做如下修改了:
public class Demo13Activity extends Activity { private ListView lv; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.mylist); lv = (ListView)findViewById(R.id.listview); SimpleAdapter adapter = new SimpleAdapter(this, getData(), R.layout.main, new String[] { "img", "title", "info" }, new int[] { R.id.img, R.id.title, R.id.info }); lv.setAdapter(adapter); }
时间: 2024-11-04 23:52:28