输入一行字符,分别统计出其中英文,空格,数字和其他字符的个数

int c = 0, space = 0, num = 0, other = 0;

char s[] = "djwiJFIW  [email protected]#$!%";

//        scanf("%s", s);

char *str = s;

while (*str != ‘\0‘) {

if ((*str >= ‘A‘ && *str <= ‘Z‘) || (*str >= ‘a‘ && *str <= ‘z‘)) {

c++;

}else if (*str == ‘ ‘){

space++;

}else if (*str >= ‘0‘ && *str <= ‘9‘){

num++;

}else{

other++;

}

str++;

printf("%c ", *str);

}

printf("英文,空格,数字和其他字符的个数分别为: %d,%d,%d,%d\n", c, space, num, other);