hdu 2602

Bone Collector

Submit Status

Description

Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave … 
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ? 

Input

The first line contain a integer T , the number of cases. 
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

Output

One integer per line representing the maximum of the total value (this number will be less than 2 ³¹).

Sample Input

1
5 10
1 2 3 4 5
5 4 3 2 1

Sample Output

14

Source

HDU 1st “Vegetable-Birds Cup” Programming Open Contest

01背包

#include <iostream>
#include <algorithm>
#include <cstring>
#include <cstdio>
#include <cmath>

using namespace std;

    int T;
    int n,v;
    const int N=1E3+5;
    int a[N],b[N],dp[N];

void ZeroOnePack(int value, int cost)
{
    for ( int i = v ; i >= cost ; i-- )
        dp[i] = max(dp[i],dp[i-cost]+value);
}

int main()
{

    scanf("%d",&T);
    while ( T-- )
    {  memset(dp,0,sizeof(dp));

        scanf("%d %d",&n,&v);
        for ( int i = 1; i <= n ; i++ )
            scanf("%d",&a[i]);
        for ( int i = 1 ; i <= n ; i++ )
            scanf("%d",&b[i]);
        for ( int i = 1 ; i <= n ; i++ )
            ZeroOnePack(a[i],b[i]);
        printf("%d\n",dp[v]);
    }
    return 0;
}