[Swift]LeetCode473. 火柴拼正方形 | Matchsticks to Square

Remember the story of Little Match Girl? By now, you know exactly what matchsticks the little match girl has, please find out a way you can make one square by using up all those matchsticks. You should not break any stick, but you can link them up, and each matchstick must be used exactly one time.

Your input will be several matchsticks the girl has, represented with their stick length. Your output will either be true or false, to represent whether you could make one square using all the matchsticks the little match girl has.

Example 1:

Input: [1,1,2,2,2]
Output: true

Explanation: You can form a square with length 2, one side of the square came two sticks with length 1. 

Example 2:

Input: [3,3,3,3,4]
Output: false

Explanation: You cannot find a way to form a square with all the matchsticks. 

Note:

1. The length sum of the given matchsticks is in the range of 0 to 10^9.
2. The length of the given matchstick array will not exceed 15.

输入为小女孩拥有火柴的数目，每根火柴用其长度表示。输出即为是否能用所有的火柴拼成正方形。

示例 1:

输入: [1,1,2,2,2]
输出: true

解释: 能拼成一个边长为2的正方形，每边两根火柴。

示例 2:

输入: [3,3,3,3,4]
输出: false

解释: 不能用所有火柴拼成一个正方形。

注意:

1. 给定的火柴长度和在 0 到 10^9之间。
2. 火柴数组的长度不超过15。

Memory Usage: 3.9 MB

 1 class Solution {
 2     func makesquare(_ nums: [Int]) -> Bool {
 3         if nums.isEmpty || nums.count < 4 {return false}
 4         var sum:Int = nums.reduce(0, +)
 5         if sum % 4 != 0 {return false}
 6         var n:Int = nums.count
 7         var all:Int = (1 << n) - 1
 8         var target:Int = sum / 4
 9         var masks:[Int] = [Int]()
10         var validHalf:[Bool] = [Bool](repeating:false,count:1 << n)
11         for i in 0...all
12         {
13             var curSum:Int = 0
14             for j in 0...15
15             {
16                 if ((i >> j) & 1) == 1
17                 {
18                     curSum += nums[j]
19                 }
20             }
21             if curSum == target
22             {
23                 for mask in masks
24                 {
25                     if (mask & i) != 0 {continue}
26                     var half:Int = mask | i
27                     validHalf[half] = true
28                     if validHalf[all ^ half] {return true}
29                 }
30                 masks.append(i)
31             }
32         }
33         return false
34     }
35 }

3911 kb

 1 class Solution {
 2     func makesquare(_ nums: [Int]) -> Bool {
 3         guard  nums.count >= 4 else { return false }
 4         let sum = nums.reduce(0, { $0 + $1 })
 5         if sum % 4 != 0 {
 6             return false
 7         }
 8         var sides: [Int] = Array(repeating: 0, count: 4)
 9         return dfs(nums.sorted(by: >), 0, &sides, sum / 4)
10     }
11
12     func dfs(_ nums: [Int], _ index: Int, _ sides: inout [Int], _ target: Int) -> Bool {
13         if index == nums.count {
14             return sides[0] == sides[1] && sides[0] == sides[2] && sides[0] == sides[3] && sides[0] == target
15         }
16
17         for i in 0 ..< sides.count {
18             if sides[i] + nums[index] > target {
19                 continue
20             }
21             sides[i] += nums[index]
22             if dfs(nums, index + 1, &sides, target) {
23                 return true
24             }
25             sides[i] -= nums[index]
26         }
27         return false
28     }
29 }

原文地址：https://www.cnblogs.com/strengthen/p/10347635.html