Verilog之Bitwise operation

1　　Bitwise operator

　　Bitwise operators perform a bit wise operation on two operands.

　　They take each bit in one operand and perform the operation with the corresponding bit in the other operand.

　　If one operand is shorter than the other, it will be extended on the left side with zeroes to match the length of the longer operand.

　　

2　　Reduction operator

　　Reduction operators are unary.

　　They perform a bit-wise operation on a single operand to produce a single bit result.

　　Reduction unary NAND and NOR operators operate as AND and OR respectively, but with their outputs negated.

　　

时间： 2025-01-13 10:02:11

Verilog之Bitwise operation的相关文章

JS魔法堂：再识Bitwise Operation & Bitwise Shift

Brief linkFly的<JavaScript-如果...没有方法>中提及如何手写Math.round方法,各种奇技淫招看着十分过瘾,最让我惊叹的是 ~~(x + 0.5 + (x >> 30)) ,完全通过加法和位运算搞定整数的四舍五入.在好奇心的驱使下重温了一下位运算,并对上述公式加以封装得到适合小数的四舍五入方法 function round(v/*alue*/, p/*recision*/){ p = Math.pow(10, p>>>31 ? 0 :

CF778B(round 402 div.2 E) Bitwise Formula

题意: Bob recently read about bitwise operations used in computers: AND, OR and XOR. He have studied their properties and invented a new game. Initially, Bob chooses integer m, bit depth of the game, which means that all numbers in the game will consis

V-rep学习笔记：串口操作

VREP Regular API提供了串口操作的相关函数,可以对串口进行打开.关闭和读写: 下面使用一款淘宝上常见的AHRS(Attitude and heading reference system,航姿参考系统)模块来驱动VREP中的虚拟模型,控制其姿态.VREP通过串口读取传感器实时发送的数据并进行解析. 传感器通过串口发送2种数据: 解算后的姿态角和气压高度等数据 原始的传感器ADC数据(直接从传感器读取出来的测量值,没有经过解算处理) 下面是VREP中以16进制显示的接收到的串口数据:

LintCode Problems Link Table

Practice Makes Perfect! # Problem Link Tag Difficulty 1 A + B problem Bitwise Operation Easy 2 Trailing Zeros Math Easy 3 Digit Counts   Medium 4 Ugly Number II   Medium 5 Kth Largest Element   Medium 6 Merge Two Sorted Arrays   Easy 7 Binary Tree Se

FZU 2105Digits Count(线段树 + 成段更新)

Description Given N integers A={A[0],A[1],...,A[N-1]}. Here we have some operations: Operation 1: AND opn L R Here opn, L and R are integers. For L≤i≤R, we do A[i]=A[i] AND opn (here "AND" is bitwise operation). Operation 2: OR opn L R Here opn,

FZU 2105 Digits Count（位数计算）

Description 题目描述 Given N integers A={A[0],A[1],...,A[N-1]}. Here we have some operations: Operation 1: AND opn L R Here opn, L and R are integers. For L≤i≤R, we do A[i]=A[i] AND opn (here "AND" is bitwise operation). Operation 2: OR opn L R Here

FindBugs规则整理

FindBugs规则整理 FindBugs是基于Bug Patterns概念,查找javabytecode(.class文件)中的潜在bug,主要检查bytecode中的bug patterns,如NullPoint空指针检查.没有合理关闭资源.字符串相同判断错(==,而不是equals)等 一.Security 关于代码安全性防护 1.Dm: Hardcoded constant database password (DMI_CONSTANT_DB_PASSWORD) 代码中创建DB的密码时采

【转】编程词汇

很实用的编程英语词库,共收录一千五百余条词汇. 第一部分: application 应用程式 应用.应用程序 application framework 应用程式框架.应用框架 应用程序框架 architecture 架构.系统架构 体系结构 argument 引数(传给函式的值).叁见 parameter 叁数.实质叁数.实叁.自变量 array 阵列 数组 arrow operator arrow(箭头)运算子 箭头操作符 assembly 装配件 assembly language 组合语

Document Object Model (DOM) Level 3 Events Specification

Document Object Model (DOM) Level 3 Events Specification W3C Working Draft 25 September 2014 This version: http://www.w3.org/TR/2014/WD-DOM-Level-3-Events-20140925/ Latest published version: http://www.w3.org/TR/DOM-Level-3-Events/ Latest editor's dr