How can I work smarter, not just harder? Ask it forever

1 >>> d={'01':95,'02':92,'03':86,'04':70}>>> print(d){'01': 95, '02': 92, '03': 86, '04': 70}>>> d['05']=80>>> print(d){'01': 95, '02': 92, '03': 86, '04': 70, '05': 80}>>> d.pop('02')92>>> print(d){'0

题目:UVA - 10131Is Bigger Smarter? (DAG) 题目大意:给出一群大象的体重和IQ.要求挑选最多的大象,组成一个序列.严格的体重递增,IQ递减的序列.输出最多的大象数目和这些大象的序列(当中一种就能够). 解题思路:DAG上的DP.和之前的一篇相似.uva437 - The Tower of Babylon(DAG上的DP).就是将每两仅仅大象满足上面的序列要求的形成一条有向边. 之后就是DAG上的DP.然后再路径输出. 代码: #include <cstdio>

题目:UVA 10131 Is Bigger Smarter 题意:给出大象的身高和体重,求身高递增且体重递减的最长序列,都是严格的,并打印序列. 分析:就是先对身高按自增排序,然后求一个单调递减子序列,严格单调的,所以加一句判断,然后打印序列,用一个数组保存就好了 开始想的是先预处理掉重复的,提交wa了,这样不行,因为你不知道体重是最高的还是最低的,可能开始留高的好,后面低的比较好.所以..... AC代码: #include<iostream> #include<cstdio>

Some people think that the bigger an elephant is, the smarter it is. To disprove this, you want to take the data on a collection of elephants and put as large a subset of this data as possible into a sequence so that the weights are increasing, but t

uva 10131 Is Bigger Smarter? 题目大意:当一只大象的体重大于另一只的体重,且智商小于另一只的智商,该大象便可以"嵌套"另一只大象.问,最长的嵌套方式.(答案不唯一) 解题思路:DAG. #include<stdio.h> #include<string.h> #include<stdlib.h> #include<algorithm> using namespace std; struct ELE{ int w

Is Bigger Smarter? The Problem Some people think that the bigger an elephant is, the smarter it is. To disprove this, you want to take the data on a collection of elephants and put as large a subset of this data as possible into a sequence so that th

Is Bigger Smarter? Time Limit: 3000MS   Memory Limit: Unknown   64bit IO Format: %lld & %llu Submit Status Description Question 1: Is Bigger Smarter? The Problem Some people think that the bigger an elephant is, the smarter it is. To disprove this, y

Description Question 1: Is Bigger Smarter? The Problem Some people think that the bigger an elephant is, the smarter it is. To disprove this, you want to take the data on a collection of elephants and put as large a subset of this data as possible in

题目:有人认为大象的体重和智力有一定的正相关性,现在给你一些数据,找到一个最长的反例序列. 分析:dp,LIS,醉倒上升子序列.对W排序求出S的最大下降子序列即可,存储路径前驱,dfs输出. 说明:先读到EOF再处理. #include <algorithm> #include <iostream> #include <cstdlib> #include <cstring> #include <cstdio> #include <cmath