AJAX提交跳转页面

在使用AJAX提交访问时对跳转网页基本不支持：

经查询解决方案为：

1）JS前台进行跳转 ；

2）后台返回脚本流：

STRUTS2

struts.xml  -->

<action name="login" method="login" class="com.hope.action.LoginAction">
<param name="code">string</param>
<param name="pass">string</param>
<result name="login" type="stream">
<param name="contentType">
text/html;charset=UTF-8
</param>
<param name="inputName">json</param>
</result>
<result name="error" type="stream">
<param name="contentType">
text/html;charset=UTF-8
</param>
<param name="inputName">json</param>
</result>
</action>

Action.java

private InputStream json;

String url = "<script language=\"JavaScript\">window.top.location.href = \"../index.jsp\";</script>";
byte[] data = url.getBytes();
this.json = new ByteArrayInputStream(data);

SPRING MVC

1  OutputStream outputStream =null;
2  String url = "<script  language=\"JavaScript\">window.top.location.href = \"../index.jsp\";</script>";
3 byte[] data = url.getBytes();
4  outputStream =response.getOutputStream();
5  outputStream.write(data);
6  outputStream.flush();
7  outputStream.close();