Given a 2D grid, each cell is either a wall 2, a zombie 1or people 0 (the number zero, one, two).Zombies can turn the nearest people(up/down/left/right) into zombies every day, but can not through wall. How long will it take to turn all people into z
大熊猫猪·侯佩原创或翻译作品.欢迎转载,转载请注明出处. 如果觉得写的不好请多提意见,如果觉得不错请多多支持点赞.谢谢! hopy ;) 该挑战的目的是僵尸碰到敌人时,将其设置为无敌模式,具体要求如下: ? You should create a variable property to track whether or not the zombie is invincible. ? If the zombie is invincible, you shouldn't bother enumer
本文简单介绍下僵尸进程. 介绍之前,首先了解一下linux中进程的6大状态. D Uninterruptible sleep (usually IO) R Running or runnable (on run queue) S Interruptible sleep (waiting for an event to complete) T Stopped, either by a job control signal or because it is being traced. W pagin
简单枚举+巧妙躲避大枚举量 #include<bits/stdc++.h> using namespace std; long long n,s1,v1,s2,v2,total; int main() { ios::sync_with_stdio(false); long long T,maxn=0; cin>>T; while(T--) { cin>>n>>s1>>v1>>s2>>v2; total=0; long lo
DescriptionGiven a 2D grid, each cell is either a wall 2, a zombie 1 or people 0 (the number zero, one, two).Zombies can turn the nearest people(up/down/left/right) into zombies every day, but can not through wall. How long will it take to turn all p