Arduino LED Matrix

Max7219 + 8x8 LED Matrix

滚动显示 I ?? U。

算法很简单，首先定义滚动画面8x32矩阵。通过generate_8x8_matrix函数生成当前循环中应当显示的8x8矩阵，通过LedControl模块的setLed设置对应的点阵即可。

不要放太久，因为times是一个int型，并未进行溢出情况的处理。

 1 #include <LedControl.h>
 2
 3 int DIN = 12;
 4 int CS =  11;
 5 int CLK = 10;
 6
 7 char TOTAL[8][32] = {
 8   {0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 1, 1, 0},
 9   {0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 0},
10   {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 0},
11   {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 0},
12   {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 0},
13   {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 0},
14   {0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 0, 0, 0, 1, 1, 1, 1, 0, 0, 0, 1, 1, 1, 1, 1, 1, 0},
15   {0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 1, 1, 1, 1, 0, 0},
16 };
17
18 void generate_8x8_matrix(char in[8][32], int current_column, char *out_matrix)
19 {
20   int lines = 8;
21   int columns = 32;
22   int i = 0;
23   int j = 0;
24   for (i = 0; i < lines; ++i)
25   {
26     for (j = current_column; j < current_column + 8; ++j)
27     {
28       out_matrix[i * lines + j - current_column] = in[i][j % columns];
29     }
30   }
31 }
32
33
34 LedControl lc = LedControl(DIN, CLK, CS, 4);
35
36 void setup() {
37   lc.shutdown(0, false);
38   lc.setIntensity(0, 8);
39   lc.clearDisplay(0);
40 }
41
42 int times = 0;
43 void loop() {
44   char matrix[64] = {0};
45   generate_8x8_matrix(TOTAL, times++, matrix);
46   int i = 0;
47   int j = 0;
48   for (i = 0; i < 8; ++i)
49   {
50     for (j = 0; j < 8; ++j)
51     {
52       lc.setLed(0, i, j, matrix[(i * 8 + j)] == 1 ? true : false);
53     }
54   }
55   delay(100);
56 }