leetcode486 Predict the Winner

思路:

博弈。

实现:

 1 class Solution
 2 {
 3 public:
 4
 5     bool PredictTheWinner(vector<int>& nums)
 6     {
 7         int dp[21][21];
 8         int n = nums.size();
 9         for (int i = 0; i < n; i++) dp[i][i] = nums[i];
10         for (int i = n - 1; i >= 0; i--)
11         {
12             for (int j = i + 1; j < n; j++)
13             {
14                 dp[i][j] = max(nums[i] - dp[i + 1][j], nums[j] - dp[i][j - 1]);
15             }
16         }
17         return dp[0][n - 1] >= 0;
18     }
19 };
时间: 2024-11-09 19:18:59

leetcode486 Predict the Winner的相关文章

LN : leetcode 486 Predict the Winner

lc 486 Predict the Winner 486 Predict the Winner Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a

LC 486. Predict the Winner

Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number will not be available for the

[LeetCode] Predict the Winner 预测赢家

Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number will not be available for the

[Leetcode] DP-- 486. Predict the Winner

Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number will not be available for the

486. Predict the Winner

Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number will not be available for the

随手练——博弈论入门 leetcode - 486. Predict the Winner

题目链接:https://leetcode.com/problems/predict-the-winner/ 1.暴力递归 当前数组左边界:i,右边界:j: 对于先发者来说,他能取到的最大值是:max(arr[i] + second(arr, i + 1, j), arr[j] + second(arr, i, j - 1)); (arr[i] + 作为后发者,在 i+1 到 j 上取得的值),(arr[j] + 作为后发者,在 i 到 j-1 上取得的值) 中大的一个. 对于后发者来说,他是被

过中等难度题目.0310

  .   8  String to Integer (atoi)    13.9% Medium   . 151 Reverse Words in a String      15.7% Medium     . 288 Unique Word Abbreviation      15.8% Medium     . 29 Divide Two Integers      16.0% Medium     . 166 Fraction to Recurring Decimal      17.

继续过中等难度.0309

  .   8  String to Integer (atoi)    13.9% Medium   . 151 Reverse Words in a String      15.7% Medium     . 288 Unique Word Abbreviation      15.8% Medium     . 29 Divide Two Integers      16.0% Medium     . 166 Fraction to Recurring Decimal      17.

LeetCode Problems List 题目汇总

No. Title Level Rate 1 Two Sum Medium 17.70% 2 Add Two Numbers Medium 21.10% 3 Longest Substring Without Repeating Characters Medium 20.60% 4 Median of Two Sorted Arrays Hard 17.40% 5 Longest Palindromic Substring Medium 20.70% 6 ZigZag Conversion Ea