Given an index k, return the kth row of the Pascal‘s triangle.
For example, given k = 3,
Return [1,3,3,1]
.
Note:
Could you optimize your algorithm to use only O(k) extra space?
Solution:
1 class Solution { 2 public: 3 vector<int> getRow(int rowIndex){ 4 vector<int> v(1,1); 5 if(rowIndex==0)return v; 6 vector<vector<int>> vec; 7 vec.push_back(v); 8 9 int n=1; 10 while(n<=rowIndex){ 11 v.clear(); 12 v.push_back(1); 13 for(int i=1;i<vec[n-1].size();i++){ 14 v.push_back(vec[n-1][i-1]+vec[n-1][i]); 15 } 16 v.push_back(1); 17 vec.push_back(v); 18 n++; 19 } 20 return v; 21 } 22 };
【LeetCode】119 - Pascal's Triangle II
时间: 2024-10-06 00:43:29