jinzhong reservoir

时间: 2025-01-12 19:44:51

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Reservoir Sampling - snapchat

首先说一下Reservoir Sampling的原理 ref: http://www.geeksforgeeks.org/reservoir-sampling/ 如果输入的Stream里面有N个数,我们需要从中选取k个随机的数,那么: 先把前k个数放入"水塘"(index范围是[0, k - 1]) 从index为[k,N - 1]中的第i个数中,随机生成一个[0, i - 1]的值r 如果r < k那么就把res[r]换成stream[i] 分析其中的概率: 对于第i个数,它被

Reservoir Sampling - 蓄水池抽样

问题起源于编程珠玑Column 12中的题目10,其描述如下: How could you select one of n objects at random, where you see the objects sequentially but you do not know the value of n beforehand? For concreteness, how would you read a text file, and select and print one random l

Reservoir Sampling

Reservoir sampling is proposed to solve such set of problems: Randomly choose items from a stream of elements where could be very large or unknown in advance, i.e., all elements in the stream are equally likely to be selected with probability The alg

Spark MLlib之水塘抽样算法(Reservoir Sampling)

1.理解 问题定义可以简化如下:在不知道文件总行数的情况下,如何从文件中随机的抽取一行? 首先想到的是我们做过类似的题目吗?当然,在知道文件行数的情况下,我们可以很容易的用C运行库的rand函数随机的获得一个行数,从而随机的取出一行,但是,当前的情况是不知道行数,这样如何求呢?我们需要一个概念来帮助我们做出猜想,来使得对每一行取出的概率相等,也即随机.这个概念即蓄水池抽样(Reservoir Sampling). 水塘抽样算法(Reservoir Sampling)思想: 在序列流中取一个数,如

Reservoir Computing论文学习

目录 背景: RC优势: 储备池计算主要理论组成: ESNS数学模型 结构表示 状态方程和输出方程 计算过程 储备池的优化 GA:使用进化算法对参数进行优化: 基于随机梯度下降法的储备池参数优化 参考文章: Reservoir Computing 背景: 神经网络的一种弥补RNN缺点 神经网 络方法在具体应用过程中也存在一些局限性 .比如前向 结构的神经网络一 般不适 合处理与 时序相 关的机 器学 习问题 , 而在实际应用中出 现的问 题往往 与时 间相关 , 比如预测 .系统辨识 .自适应滤

reservoir sampling / random shuffle

randomly choose a sample of k items from a list S containing n elements, the algorithm may be online (i.e. the input list is unknown beforehand) https://en.wikipedia.org/wiki/Reservoir_sampling ReserviorSampling(Source[1..n], Result[1..k]) { for (int

Reservoir Sampling 蓄水池抽样算法,经典抽样

随机读取数据,如何保证真随机是不可能的,因为计算机的随机函数是伪随机的. 但是在不考虑计算机随机函数的情况下,如何保证数据的随机采样呢? 1.系统提供的shuffle函数 C++/Java都提供有shuffle函数,可以对容器内部的数据打乱,保持随机排序. C++: 1 template <class RandomAccessIterator, class URNG> 2 void shuffle (RandomAccessIterator first, RandomAccessIterato

68. 蓄水池抽样(Reservoir Sampling)

[本文链接] http://www.cnblogs.com/hellogiser/p/reservoir-sampling.html 问题起源于编程珠玑Column 12中的题目10,其描述如下: How could you select one of n objects at random, where you see the objects sequentially but you do not know the value of n beforehand? For concreteness

leetcode_398 Random Pick Index(Reservoir Sampling)

Given an array of integers with possible duplicates, randomly output the index of a given target number. You can assume that the given target number must exist in the array. Note:The array size can be very large. Solution that uses too much extra spa