使用WebView可以让Android端的开发工作大量减少，原因是在服务端可以为其做一定的工作，下面这个小Demo就实现了从Android客户端与服务端的交互。我这里客户端使用的工具是Eclipse，服务端使用MyEclipse。
实现效果图：
客户端：
点击登录按钮后，页面跳转，而在服务端Console中看到如下（只看最后一行即可）：
可以看到服务端收到了客户端发过来的用户名：yao。
源代码：
客户端：
activity_main:
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:paddingBottom="@dimen/activity_vertical_margin"
android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin"
tools:context=".MainActivity" >
<WebView
android:id="@+id/webView"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:layout_centerHorizontal="true" />
</RelativeLayout>
MainActivity：
package com.webviewdemo1;
import android.app.Activity;
import android.app.AlertDialog;
import android.content.DialogInterface;
import android.content.DialogInterface.OnClickListener;
import android.os.Bundle;
import android.webkit.JsResult;
import android.webkit.WebChromeClient;
import android.webkit.WebSettings;
import android.webkit.WebView;
public class MainActivity extends Activity {
private WebView webView;
/**
* 服务端地址
*/
private String url = "http://172.16.17.36:8080/mywebviewserver/myhtml.html";
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
webView = (WebView) findViewById(R.id.webView);
WebSettings webSettings = webView.getSettings();
webSettings.setJavaScriptEnabled(true);
webView.setWebChromeClient(new WebChromeClient(){
@Override
public boolean onJsAlert(WebView view, String url, String message,
final JsResult result) {
AlertDialog.Builder builder = new AlertDialog.Builder(MainActivity.this);
builder.setTitle("警告");
builder.setMessage(message);
builder.setPositiveButton("ok", new OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
result.confirm();
}
});
builder.create().show();
return true;
}
});
webView.loadUrl(url);
}
}
服务端：
myhtml.html:
<!DOCTYPE html>
<html>
<head>
<title>myhtml.html</title>
<meta http-equiv="content-type" content="text/html; charset=UTF-8">
<!--客户端访问服务端的URL地址：
http://172.16.17.36:8080/mywebviewserver/myhtml.html
-->
<script type="text/javascript">
function dosubmit() {
var th = document.form1;
if (th.username.value == "") {
alert("请输入用户名称！！");
return;
}
th.action = "/mywebviewserver/servlet/Login";
}
</script>
</head>
<body>
<form name="form1" action="" method="post">
<table border="1" bordercolor="#CCCCCC" cellpadding="1" width="300"
cellspacing="1">
<tr>
<td align="right">用户名</td>
<td><input type="text" name="username" value=""></td>
</tr>
<tr>
<td align="right">密码</td>
<td><input type="password" name="pswd" value=""></td>
</tr>
<tr>
<td colspan="2" align="center"><input type="submit"
name="submit" value="登陆" onclick="dosubmit()"> <input
type="reset" name="reset" value="重置">
</td>
</tr>
</table>
</form>
</body>
</html>
Login.java:
package com.cn.login;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class Login extends HttpServlet {
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
}
public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html;chareset=utf-8");
PrintWriter out = response.getWriter();
String name = request.getParameter("username");
System.out.println("---客户端输入的用户名为:->>>" + name);
out.flush();
out.close();
}
}
下面给出客户端和服务端的源代码，感兴趣的可以试着运行一下：
Android WebView与服务端交互Demo
时间： 2024-10-09 08:57:50