Can you solve this equation?

Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other)

Total Submission(s) : 28   Accepted Submission(s) : 17

Problem Description

Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;

Now please try your lucky.

Input

The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);

Output

For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.

Sample Input

2
100
-4

Sample Output

1.6152
No solution!

 

 

AC_code:
#include<stdio.h>
#include<math.h>
double f(double x)
{
	return 8*x*x*x*x+ 7*x*x*x + 2*x*x + 3*x + 6;
}
int main()
{
	int n;
	double y,mid,l,r;
	scanf("%d",&n);
	while(n--)
	{
		scanf("%lf",&y);
		if(y<f(0)||y>f(100))
			printf("No solution!\n");
		else
		{
			l=0;r=100;
			while(r-l>1e-10)
			{
				mid=(r+l)/2;
				 if(f(mid)<y)
					l=mid+1e-10;
				else
					r=mid-1e-10;
			}
			printf("%.4lf\n",mid);
		}
	}
	return 0;
}

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